Suppose that the magnetic dipole moment of Earth is 6.5 x 1026 J/T. (a) If the origin of this magnetism were a magnetized iron sphere at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? The radius of Earth is 6.37 × 106 m. Assume complete alignment of the dipoles. The density of Earth's inner core is 12 g/cm³. The magnetic dipole moment of an iron atom is 2.1 x 10-23 J/T. Iron has a molar mass of 55.9 g/mol. (Note: Earth's inner core is in fact thought to be in both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth's magnetism has been ruled out by several considerations. For one, the temperature is certainly above the Curie point.) (a) Number i Units (b) Number i Units
Suppose that the magnetic dipole moment of Earth is 6.5 x 1026 J/T. (a) If the origin of this magnetism were a magnetized iron sphere at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? The radius of Earth is 6.37 × 106 m. Assume complete alignment of the dipoles. The density of Earth's inner core is 12 g/cm³. The magnetic dipole moment of an iron atom is 2.1 x 10-23 J/T. Iron has a molar mass of 55.9 g/mol. (Note: Earth's inner core is in fact thought to be in both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth's magnetism has been ruled out by several considerations. For one, the temperature is certainly above the Curie point.) (a) Number i Units (b) Number i Units
Related questions
Question
![Suppose that the magnetic dipole moment of Earth is 6.5 x 1026 J/T. (a) If the origin of this magnetism were a magnetized iron sphere
at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? The radius of
Earth is 6.37 x 106 m. Assume complete alignment of the dipoles. The density of Earth's inner core is 12 g/cm3. The magnetic dipole
moment of an iron atom is 2.1× 10 23 J/T. Iron has a molar mass of 55.9 g/mol. (Note: Earth's inner core is in fact thought to be in
both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth's magnetism has been ruled out by
several considerations. For one, the temperature is certainly above the Curie point.)
(a) Number
i
Units
(b) Number
i
Units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F61bd262a-2b58-4236-876d-86aa8f337b18%2F10659dbd-9ffc-4da5-b6a9-9d99014552ef%2Fnv9c0ug_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose that the magnetic dipole moment of Earth is 6.5 x 1026 J/T. (a) If the origin of this magnetism were a magnetized iron sphere
at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? The radius of
Earth is 6.37 x 106 m. Assume complete alignment of the dipoles. The density of Earth's inner core is 12 g/cm3. The magnetic dipole
moment of an iron atom is 2.1× 10 23 J/T. Iron has a molar mass of 55.9 g/mol. (Note: Earth's inner core is in fact thought to be in
both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth's magnetism has been ruled out by
several considerations. For one, the temperature is certainly above the Curie point.)
(a) Number
i
Units
(b) Number
i
Units
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)