An electron is accelerated through 2.10 103 V from rest and then enters a uniform 2.40-T magnetic field.(a) What is the maximum magnitude of the magnetic force this particle can experience? N(b) What is the minimum magnitude of the magnetic force this particle can experience? **Magnetic Force on an Electron**An electron is accelerated through a potential difference of \(2.10 \times 10^3\) volts from rest and then enters a uniform magnetic field of \(2.40\) teslas.**(a)** What is the maximum magnitude of the magnetic force this electron can experience?- [Answer box] N**(b)** What is the minimum magnitude of the magnetic force this electron can experience?- \([0]\) N (Answer is marked correct with a checkmark)**Explanation:**When an electron moves in a magnetic field, it experiences a magnetic force. This force depends on the velocity of the electron and the angle between the velocity vector and the magnetic field. The force is maximized when the velocity is perpendicular to the magnetic field, calculated with the formula:\[ F = qvB \sin(\theta) \]where:- \( F \) is the magnetic force- \( q \) is the charge of the electron- \( v \) is the velocity of the electron- \( B \) is the magnetic field strength- \( \theta \) is the angle between the velocity and the magnetic fieldThe force is minimized at zero when the electron moves parallel to the magnetic field (\(\theta = 0^\circ\) or \(180^\circ\)).This problem involves calculating the maximum possible force and understanding when the force can be zero.

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An electron is accelerated through 2.10 103 V from rest and then enters a uniform 2.40-T magnetic field. (a) What is the maximum magnitude of the magnetic force this particle can experience? N (b) What is the minimum magnitude of the magnetic force this particle can experience?