A loop of wire is at the edge of a region of space containing a uniform magnetic field B⃗. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area Aof the coil inside the magnetic field region is decreasing at the constant rate ccc. That is, dA/dt=−c, with c>0. For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area c=−dA/dt?

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A loop of wire is at the edge of a region of space containing a uniform magnetic field B⃗. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area Aof the coil inside the magnetic field region is decreasing at the constant rate ccc. That is, dA/dt=−c, with c>0. For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area c=−dA/dt?

**Transcription for Educational Website**

---

### Understanding Magnetic Induction in a Loop of Wire

**Concept Overview:**

A loop of wire is positioned at the boundary of a spatial region containing a uniform magnetic field, denoted as \(\vec{B}\). The loop's plane is orthogonal to the magnetic field. When the loop is gradually pulled from this region, the area \(A\) of the coil that remains within the magnetic field diminishes at a constant rate \(c\). Mathematically, this is expressed as:

\[
\frac{dA}{dt} = -C, \quad \text{where } C > 0.
\]

**Part B: Rate of Change of Area**

For a square loop with side length \(L\) being extracted from the magnetic field at a uniform speed \(v\) (see accompanying figure), the task is to determine the rate of change of area \(C\), given by \(-\frac{dA}{dt}\).

**Express your answer in terms of \(L\) and \(v\).**

Here's the equation provided by the user:

\[
C = \frac{L^2}{v}
\]

*Note: This submission is currently incorrect, and recalculations may be necessary. Attempts remaining: 2.*

**Figure Explanation:**

The figure illustrates a square loop within a magnetic field indicated by a grid of "X" symbols, which denotes the field directed into the plane. The loop's side is marked as \(L\), and it's being pulled to the right at a constant speed \(v\).

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For further inquiry or discussion, feedback can be provided through the respective section.
Transcribed Image Text:**Transcription for Educational Website** --- ### Understanding Magnetic Induction in a Loop of Wire **Concept Overview:** A loop of wire is positioned at the boundary of a spatial region containing a uniform magnetic field, denoted as \(\vec{B}\). The loop's plane is orthogonal to the magnetic field. When the loop is gradually pulled from this region, the area \(A\) of the coil that remains within the magnetic field diminishes at a constant rate \(c\). Mathematically, this is expressed as: \[ \frac{dA}{dt} = -C, \quad \text{where } C > 0. \] **Part B: Rate of Change of Area** For a square loop with side length \(L\) being extracted from the magnetic field at a uniform speed \(v\) (see accompanying figure), the task is to determine the rate of change of area \(C\), given by \(-\frac{dA}{dt}\). **Express your answer in terms of \(L\) and \(v\).** Here's the equation provided by the user: \[ C = \frac{L^2}{v} \] *Note: This submission is currently incorrect, and recalculations may be necessary. Attempts remaining: 2.* **Figure Explanation:** The figure illustrates a square loop within a magnetic field indicated by a grid of "X" symbols, which denotes the field directed into the plane. The loop's side is marked as \(L\), and it's being pulled to the right at a constant speed \(v\). --- For further inquiry or discussion, feedback can be provided through the respective section.
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