A loop of wire is at the edge of a region of space containing a uniform magnetic field B⃗. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area Aof the coil inside the magnetic field region is decreasing at the constant rate ccc. That is, dA/dt=−c, with c>0. For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area c=−dA/dt?

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Chapter12: Sources Of Magnetic Fields
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A loop of wire is at the edge of a region of space containing a uniform magnetic field B⃗. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area Aof the coil inside the magnetic field region is decreasing at the constant rate ccc. That is, dA/dt=−c, with c>0. For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area c=−dA/dt?

A loop of wire is at the edge of a region of space
containing a uniform magnetic field B. The plane of the
loop is perpendicular to the magnetic field. Now the loop
is pulled out of this region in such a way that the area A
of the coil inside the magnetic field region is decreasing
dA
at the constant rate c. That is, =-C, with c> 0.
dt
Figure
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1 of 1
V
magnetic field through the loop (about which you may have studied earlier) and from the change in the area of
the loop (within the magnetic field region), as in this problem.
Part B
For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the
dA
figure), what is the rate of change of area C =
dt
-? (Figure 1)
Express your answer in terms of L and v.
► View Available Hint(s)
C =
[ΠΙ ΑΣΦ
Submit
L²
V
Provide Feedback
Previous Answers Request Answer
?
X Incorrect; Try Again; 2 attempts remaining
Next >
Transcribed Image Text:A loop of wire is at the edge of a region of space containing a uniform magnetic field B. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area A of the coil inside the magnetic field region is decreasing dA at the constant rate c. That is, =-C, with c> 0. dt Figure X X X X X X X X X X X x XXXXX x x x XXX XXXX X XXXX XXXXXXXXXXXX XXX XXXX X X X X X xxx XXX xXx XXXX X XX XX XXXXXX XXXX X XXXX XXXX Xx XXXXXXX XX X X X X X X X X X X XX XXXXXXXX XX X X X X X X XXXX XXX XXXX X X XXXXXXXX XXXX XXXXXXXXXXX XX XXXXX XX XXXXXXX XX X 1 of 1 V magnetic field through the loop (about which you may have studied earlier) and from the change in the area of the loop (within the magnetic field region), as in this problem. Part B For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the dA figure), what is the rate of change of area C = dt -? (Figure 1) Express your answer in terms of L and v. ► View Available Hint(s) C = [ΠΙ ΑΣΦ Submit L² V Provide Feedback Previous Answers Request Answer ? X Incorrect; Try Again; 2 attempts remaining Next >
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