12 = -aý cos p + aê sin o 13 = -l1 14 = -12 is â Bo everywhere.
Related questions
Question
![a rectangular wire loop carries current 1, nas height b, width a, and is
centered on the origin. It can rotate about the z axis. For rotation angle o, the surface normal of
the rectangle enclosed by the loop is î = âu cos o + ý sin ø, and the vectors representing the four
sides of the loop are
1 = bê
12 = -aý cos o + aâ sin ø
13 = -l1
14 = -12
%3D
The magnetic flux density is & Bo everywhere.
(a) What is the magnetic flux through the loop as a function of ø?
12 =
-aỹ cos o
+aî sin ø
1 = bê
13
-1
în = âr cos o
B = &B
I4 =
+ ŷ sin ø
-12
ntine i.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab46a0ea-17d6-40e4-a6a7-497d3a3101a5%2F55ec7a10-a8fe-41e3-b714-fc7631c300ef%2Fpt0oyx_processed.png&w=3840&q=75)
Transcribed Image Text:a rectangular wire loop carries current 1, nas height b, width a, and is
centered on the origin. It can rotate about the z axis. For rotation angle o, the surface normal of
the rectangle enclosed by the loop is î = âu cos o + ý sin ø, and the vectors representing the four
sides of the loop are
1 = bê
12 = -aý cos o + aâ sin ø
13 = -l1
14 = -12
%3D
The magnetic flux density is & Bo everywhere.
(a) What is the magnetic flux through the loop as a function of ø?
12 =
-aỹ cos o
+aî sin ø
1 = bê
13
-1
în = âr cos o
B = &B
I4 =
+ ŷ sin ø
-12
ntine i.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given:
To find the magnetic flux through the loop is given as,
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)