Algebra students in a local high school use a computer-based program to brush up on algebra skills to be assessed by a test. The program claims that 80% of students using the program will pass the test. After an early pilot of the new program, only 33 of 50 students passed the test.A 1-proportion z test is going to be conducted to see if there's evidence that the true passing rate is less than what was claimed. The null hypothesis is p = 0.80.USE SALT(a) What is the alternative hypothesis?OH₂: p > 0.80ⒸH₂: P = 0.80ⒸH₂: P < 0.80OH₂: P = 0.80(b) What is the value of z, the test statistic? (Round your answer to two decimal places.)z =x(c) What is the P-value? (Use a table or technology. Round your answer to four decimal places.)x

Claim: 80% of students using the program will pass the test.Sample size Number of students passed…

Answered: a local high school use a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Edllon. J2 THiles per gallon when it is QUESTION 7 Find the P-value for the indicated hypothesis test. In a sample of 88 children selected randomly from one town, it is found that 8 of them suffer from asthma. Find the P-value for a test of the claim that the proportion of all children in the town who suffer from asthma is equal to 119%. 0.2843 -0.2843 0.2157 O 0.5686 QUESTION 8 for the indicated hypothesis test. fathers take no responsibility for
Scientists suspect that females can smell a particular chemical with an intensity greater than that of males. It is understood that there is a genetic component which affects the sensitivity to this chemical as well. 7 sets of full blood siblings are put near the chemical and asked to rate its intensity on a scale of 0 to 10. (0 means cannot smell.) Here are the results:Please state: 1. Qualitative (Categorical) or Quantitative (Numeric)• If Qualitative: Goodness of Fit or Test of Homogeneity/Independence?• If Quantitative: Proportions or Means?2. State the null and alternative hypotheses. 3. What distribution would you use to conclude the test, assuming all necessary assumptions weresatisfied? If Degrees of Freedom are involved, state them.
In recent years, approximately 55% of eligible voters take the time to vote in presidential elections. A poll based on a random sample of 200 eligible voters finds that 128 plan to vote in the next presidential election. Does this data provide convincing evidence at the ?α = 0.05 level that the proportion of eligible voters who will take time to vote in the next presidential election differs from 0.55?
Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80H0:p=0.80 versus Ha:p≠0.80Ha:p≠0.80 and calculates a test statistic of 1.10 with a pp-value of 0.273. Which of the following best represents the meaning of the pp-value? If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273. A If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273. B If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273. C If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273. D If the…
Historically it is known thatp = 36.3% of the population have a specified characteristic. A random sample of size n=500 is taken, and x=167 number of the population has the specified characteristic. Determine the value of the test statistic for the hypothesis test of one proportion with null hypothesis Ho: p = 36.3%. Enter your answer to two decimal places.
You hear on the local news that for the city of Kalamazoo, the proportion of people who support President Trump is 0.42. However, you think it is less than 0.42. The hypotheses you want to test are Null Hypothesis: p ≥ 0.42, Alternative Hypothesis: p < 0.42. You take a random sample around town and calculate a p-value for your hypothesis test of 0.7963. What is the appropriate conclusion? Conclude at the 5% level of significance. Question 4 options: 1) We did not find enough evidence to say the proportion of people who support President Trump is larger than 0.42. 2) We did not find enough evidence to say a significant difference exists between the proportion of people who support President Trump and 0.42 3) The proportion of people who support President Trump is significantly less than 0.42. 4) We did not find enough evidence to say the proportion of people who support…
please check this. The recidivism rate for convicted sex offenders is 14%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 324 convicted sex offenders who were also drug addicts, 32 of them became repeat offenders. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 14% at αα = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders…
I just want the correct answer (A or B or C or D)I do not want the solution steps in the answer
Suppose the national average dollar amount for an automobile insurance claim is $777.86. You work for an agency in Michigan and you are interested in whether or not the state average is less than the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 777.86, Alternative Hypothesis: μ < 777.86. You take a random sample of claims and calculate a p-value of 0.0232 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance. Question 9 options: 1) The true average claim amount is significantly different from $777.86. 2) The true average claim amount is significantly less than $777.86. 3) The true average claim amount is significantly higher than $777.86. 4) We did not find enough evidence to say the true average claim amount is less than $777.86. 5) The true average claim…
A sample of patients is tested to determine if they have any hospital borne infections. How large of a sample must be collected to be accurate within 0.01 at the 1% level of significance, if the hospital estimates the true proportion of patients infected is 0.045? p̂ = q̂ = E = Z= n=
Can you please help me with this statistics last math problem? Thank you!
OC. None of the above QUESTION 7 In testing the hypotheses H₂=0.40, H¸:л>0.40, at 5 % level of significance. if the sample proportion is 0.45 an 0 the sample size is 49; which one of the following statements is incorrect? O A. A one-tail is used. OB. The standard error is 0.0070 O C. The test statistic is 0.7143 OD. p-value is 0.2389 Click Save and Submit to save and submit. Click Save All Answers to save all answers. 0 H 2 Enjoy a

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