A light spring of force constant k = 160 N/m rests vertically on the bottom of alarge beaker of water (see figure (a)).A 5.00-kg block of wood (density = 650 kg/m3) is connected to the spring, and the block–spring system is allowed to come to static equilibrium (see figure (b)).What is the elongation ΔL of the spring?Include a free-body diagram for the block.(Hint: Begin your derivation with equilibrium: “ΣF = 0”. The derivation is a little complex, so don’t give up, and don’t be tempted to calculate the numerical answer in pieces.) The image illustrates two scenarios involving a spring submerged in a liquid. **Diagram (a):**- A spring with spring constant \( k \) is vertically submerged in a liquid within a container. - The spring is in its relaxed, unstretched state with no additional mass attached. - The parameter \( \Delta L \) is indicated, potentially representing a change in length when a force or mass is applied.**Diagram (b):**- The same spring \( k \) is shown, but now a mass \( m \) is attached to its top end.- The spring is stretched due to the weight of the mass \( m \), resulting in an extension denoted by \( \Delta L \). In both diagrams, the spring is entirely submerged in the liquid. The setup likely aims to illustrate concepts such as Hooke's Law, buoyancy, or the combined effect of forces in a fluid. The extension \( \Delta L \) in diagram (b) compared to diagram (a) allows for exploration of how different forces (gravity, buoyancy) affect the spring-mass system.

As the when the mass is attached to the springthe equilibrium attended by spring system and the…

Answered: A light spring of force constant k =…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A light spring of force constant k = 160 N/m rests vertically on the bottom of a
large beaker of water (see figure (a)).
A 5.00-kg block of wood (density = 650 kg/m3) is connected to the spring, and the block–spring system is allowed to come to static equilibrium (see figure (b)).
What is the elongation ΔL of the spring?
Include a free-body diagram for the block.
(Hint: Begin your derivation with equilibrium: “ΣF = 0”. The derivation is a little complex, so don’t give up, and don’t be tempted to calculate the numerical answer in pieces.)

The image illustrates two scenarios involving a spring submerged in a liquid.

**Diagram (a):**
- A spring with spring constant \( k \) is vertically submerged in a liquid within a container.
- The spring is in its relaxed, unstretched state with no additional mass attached.
- The parameter \( \Delta L \) is indicated, potentially representing a change in length when a force or mass is applied.

**Diagram (b):**
- The same spring \( k \) is shown, but now a mass \( m \) is attached to its top end.
- The spring is stretched due to the weight of the mass \( m \), resulting in an extension denoted by \( \Delta L \).

In both diagrams, the spring is entirely submerged in the liquid. The setup likely aims to illustrate concepts such as Hooke's Law, buoyancy, or the combined effect of forces in a fluid. The extension \( \Delta L \) in diagram (b) compared to diagram (a) allows for exploration of how different forces (gravity, buoyancy) affect the spring-mass system.

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