A librarian can't see objects clearly beyond his far point of 437 cm. Determine the power of the contact lens needed to correct his vision. D What type of lens is needed? diverging lens O converging lens Additional Materials O Reading
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Q: A librarian can't see objects clearly beyond his far point of 438 cm. Determine the power of the…
A: Given Data :- The focal length is f = 438 cm.
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A: It is given that,The focal length of the lens is f=-9.7 cm.The object distance is u=13.3 cm.
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- A person can comfortably focus on an object that is 49.0 cm from their eye. They wish to wear a contact lens that allows them to focus comfortably an object that is only 10.0 cm from the eye. a) What is the focal length of the contact lens they should wear? b) The contact lens is: O Need to know if the person is near sighted or far sighted to determine O Not enough information O A converging lens O A diverging lens c) When they wear this contact lens described above, what happens to their distance vision? O Their far point gets closer o Their far point moves farther away O Vision correction for close objects does not effect vision for far away ojects cmCreate a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.O Resources A farsighted eye is corrected by placing a converging lens in front of the eye. The lens will create a virtual image that is located at the near point (the closest an object can be and still be in focus) of the viewer when the object is held at a comfortable distance, usually taken to be 25.0 cm. If a person has a near point of 31.5 cm, what power reading glasses should be prescribed to treat this hyperopia? Assume that the distance from the eye to the lens is negligible. diopters power:
- A severely myopic patient has a far point of 3.35 cm. By how many diopters should the power of his eye be reduced in laser vision correction to obtain normal distant vision for him? (Assume a lens-to-retina distance of 2.00 cm.) Additional Materials O ReadingA librarian can't see objects clearly beyond his far point of 486 cm. Determine the power of the contact lens needed to correct his vision. D What type of lens is needed? O diverging lens O converging lensA plano-concave lens for an underwater camera is shown below. It's diopter under water is -8.33. The radius of curvature of its front surface is 8 cm. Assuming that the index of fraction ofwater is 1.33, what is the index of fraction of the substance of which this lens it is made? a. 2.00 b. 1.81 c. 1.52 d. 1.67
- Which of the following changes would increase the focal length of a lens? O increase index of refraction of lens material. O increase radius of curvature of surface. O decrease radius of curvature of surface. use red colored lens material.Question 1 A diverging lens has a focal length of 10 cm. An object is placed at a Not complete distance of 15 cm to the left of the lens. What is the image position? Marked out of 10.00 Select one: P Flag 10 cm to the left of the lens а. question O b. 6 cm to the left of the lens О с. 6 cm to the right of the lens O d. 15 cm to the left of the lens е. 15 cm to the right of the lens CheckAn object is held 76.7 cm away from a lens. The lens has a focal length of 78.3 cm. A.) Determine the image distance. -3753 cm B.) Determine the magnification. 48.93 C.) If the object is 6.3 cm long, determine the image height. 308.25 cm D.) Which of the following are true about the image? Choose all that are true. O The image is magnified. u The image is inverted. The image is virtual. - The image is diminished. The image is real. - The image is upright. E.) Which of the following are true about the lens? Choose all that are true. The lens is concave. The lens is diverging. M The lens is converging. M The lens is convex.