A leaf of length h is positioned d 71.9 cm in front of a converging lens with a focal length of 35.0 cm. An observer views the image of the leaf from a position 1.26 m behind the lens, as shown in the figure below. Leaf 1.26 m (a) What is the magnitude of the lateral magnification (the ratio of image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the leaf directly? Need Help? Read It Master It
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- A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.28 mm. With the length of the barrel set at 35.0 cm, the diameter of a red blood cell's image subtends an angle of 1.43 mrad with the eye. If the final image distance is 35.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this equation, go back to basics and use the thin-lens equation. um= A leaf of length his positioned d below. Leaf d 70.3 cm in front of a converging lens with a focal length of 34.0 cm. An observer views the image of the leaf from a position 1.26 m behind the lens, as shown in the figure 1.26 m (a) What is the magnitude of the lateral magnification (the ratio of image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the leaf directly?Two converging lenses create an image 1.50 m away from the obiect. The first lens is placed 30 cm in front of the object. The first lens has a focus length of 20 cm and the second has a focus length of 15 cm. How far apart are the lenses be (x=?)? Drawing not to scale. X=? 30 cm 1.5 m
- an object of height 5 cm is placed 20 cm in front of a converging lens at focal length 10 cm. Behind the converging lens, and 25cm from it, there is a diverging lens of the focal length of 6 cm. Find the location of the final image, in centimeters, with respect to teh diverging lens. what is the magnification of the final image? what is the height of the final image?An object is 6 cm in front of a converging lens with a focal length of 10cm. Draw a ray diagram (to scale with a ruler) to find the location of the image. Is the image upright or inverted, and Is the image real or virtual? Then I want to use the thin lens formula to find the image distance and the magnification. I got stuck in the middle of this problem and am confused. Thank you for the help!The projection lens in a certain slide projector is a single thin lens. A slide 23.0 mm high is to be projected so that its image fills a screen 1.90 m high. The slide-to-screen distance is 3.06 m. (Enter your answers to at least one decimal place.) (a) Determine the focal length of the projection lens. mm(b) How far from the slide should the lens of the projector be placed to form the image on the screen? mm
- A thin lens is comprised of two spherical surfaces with radii of curvatures of 32.4 cm for the front side and -26.9 cm for the back side. The material of which the lens is compose has an index of refraction of 1.49. What is the magnification of the image formed by an object placed 43.7cm from the lens?In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube length is 25 cm. What is the magnitude of the overall magnification of the microscope?An object of height 9.00 cm is placed 26.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm cm (d) Is the image real or virtual? real virtual (e) Is the image upright or inverted? upright inverted
- A converging lens of focal length f=2 cm is used to focus the image of an object onto a screen. The object and screen are separated by 15 cm. The lens is placed between the object and the screen, at a distance from the screen such that the image of the object is focused into the screen. At what distance from the screen must the lens be placed in order to have an image magnification < 1? Provide your answer to two significant figures. distance = cm.The figure shows an object and its image formed by a thin lens. Assume that d1 = 0.919 m, d2 = 0.861 m, and h = 7.50E-2 m. What is the image height (in m; answer sign and magnitude)?A system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…