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A large mixing tank initially contains 1000 gallons of water in which 40 pounds of salt have been dissolved. Another brine solution is pumped into the tank at the rate of 5 gallons per minute, and the resulting mixture is pumped out at the same rate. The concentration of the incoming brine solution is 3 pounds of salt per gallon. If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is dA = 3 – 0.005A dt dA = 5 – 0.05A dt dA = 15 – 0.005A dt dA = 3 – 0.05A dA 15 + 0.05A dt

A large mixing tank initially contains 1000 gallons of water in which 40 pounds of salt have been dissolved. Another brine solution is pumped into the tank at the rate of 5 gallons per minute, and the resulting mixture is pumped out at the same rate. The concentration of the incoming brine solution is 3 pounds of salt per gallon. If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is dA = 3 – 0.005A dt dA = 5 – 0.05A dt dA = 15 – 0.005A dt dA = 3 – 0.05A dA 15 + 0.05A dt

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A large mixing tank initially contains 1000 gallons of water in which 40 pounds of salt have been dissolved. Another brine solution is pumped into the tank at the rate of 5 gallons per minute, and the resulting mixture is pumped out at the same rate. The concentration of the incoming brine solution is 3 pounds of salt per gallon. If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is dA dt 3 – 0.005 A %3D dA 5 – 0.05A dt dA 15 – 0.005A %3D dt dA = 3 – 0.05A dt dA 15 + 0.05A dt
Transcribed Image Text:A large mixing tank initially contains 1000 gallons of water in which 40 pounds of salt have been dissolved. Another brine solution is pumped into the tank at the rate of 5 gallons per minute, and the resulting mixture is pumped out at the same rate. The concentration of the incoming brine solution is 3 pounds of salt per gallon. If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is dA dt 3 – 0.005 A %3D dA 5 – 0.05A dt dA 15 – 0.005A %3D dt dA = 3 – 0.05A dt dA 15 + 0.05A dt
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