A LaGuardia Physics Professor drops a stone into a well. How deep is the well if the Professor hears the sound from the stone hitting the bottom of the well 1.9 s later? Neglect the air resistance and take the free fall acceleration g = 9.81 m/s². The air temperature is T = 24.5°C. Hint: = g.t² Try to set the following equations: (1) for the stone to fall down, h -; (2) for the sound to travel 2 back to the surface, h = ct₂; and (3) for the delay time, t = t₁ + t2. You have 3 equations and 3 unknown variables: t₁, t2, and h. And, of course, you will need the speed of sound at the given air temperature: c = (331.3 +0.606 T) m/s. The depth of the well, h = 17.707 x Units m How long did it take for the sound to travel back? The time, ts = Units Select an answer

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A LaGuardia Physics Professor drops a stone into a well. How deep is the well if the Professor hears the
sound from the stone hitting the bottom of the well 1.9 s later? Neglect the air resistance and take the free
fall acceleration g = 9.81 m/s². The air temperature is T = 24.5°C.
Hint:
g.t²
Try to set the following equations: (1) for the stone to fall down, h = -; (2) for the sound to travel
2
back to the surface, h = c · t2; and (3) for the delay time, t = t₁ + t2. You have 3 equations and 3
unknown variables: t₁, t2, and h. And, of course, you will need the speed of sound at the given air
temperature: c = (331.3 +0.606 · T) m/s.
The depth of the well, h = 17.707 X Units m
How long did it take for the sound to travel back?
The time, ts
=
Units Select an answer ✓
Transcribed Image Text:A LaGuardia Physics Professor drops a stone into a well. How deep is the well if the Professor hears the sound from the stone hitting the bottom of the well 1.9 s later? Neglect the air resistance and take the free fall acceleration g = 9.81 m/s². The air temperature is T = 24.5°C. Hint: g.t² Try to set the following equations: (1) for the stone to fall down, h = -; (2) for the sound to travel 2 back to the surface, h = c · t2; and (3) for the delay time, t = t₁ + t2. You have 3 equations and 3 unknown variables: t₁, t2, and h. And, of course, you will need the speed of sound at the given air temperature: c = (331.3 +0.606 · T) m/s. The depth of the well, h = 17.707 X Units m How long did it take for the sound to travel back? The time, ts = Units Select an answer ✓
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