A laboratory sample of clay 2 cm thick took 15 min to attain 60 percent consolidation under a double drainage condition. What time (in days) will be required to attain the same degree of consolidation for a clay layer 3 m thick under the foundation of a building for a similar loading and drainage condition? a.17.15 b.119 c.234 d.564.3

Q: The figure shows the soil profile at a site where you plan to lower the water table. You have…

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Q: For a laboratory consolidation test on a clay specimen (drained on both sides) the following results…

A: P1 is equal to 50 KpaP2 is equal to 120 Kpae1 is equal to .92e2 is equal to 0.78Time…

Q: A consolidation test has been performed on a sample obtained from a saturated clay at a point 12m…

A: To determine is the given soil is under consolidated, normally consolidated or over consolidated.…

Q: A clay layer 5 m thick has double drainage. It was consolidated under a load of 127.5 kN/m2. The…

A: Given Data:Thickness of layer=5mdouble drainageLoad=127.5 kN/m2Increased load=197.5 kN/m2Coefficient…

Q: A 3-m thick layer of saturated clay (two-way drainage) under a surcharge loading underwent 90%…

A: Thickness of saturated clay layer, H= 3 m Drainage condition = 2 way drainage  Degree of…

Q: A 10 m thick clay layer overlying an impermeable rock is consolidated under an overburden pressure…

A: H = 10 m  = 500 kPa = 300 kPa

Q: 4. Ina consolidated drained tri-axial text on a normally consolidated clay soil a deviator stress of…

A: Step 1

Q: A stratum of normally consolidated clay is 25 feet thick and the water content is 3. measured as 50%…

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Q: 3- The time for 65% consolidation of a 1.12-inch clay specimen (drained at top and bottom) in the…

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Q: 10.9 A consolidation test on a sample of clay produced the following data: o: (kPa) 8. 16 32 64 128…

A: “Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: 4. (a) Time required for a 3m clay layer, sitting on bedrock, and overlain by a sand layer to fully…

A: Time required for consolidation settlement, t = Tv d2/Cv Where, Tv = Non-dimensional time factor d =…

Q: 2.17 A clay specimen 25 mm thick (drained at top only) was tested in the laboratory. For a given…

A: The objective of this problem is to determine the time required for  consolidation of a clay layer…

Q: 3. A 15 ft thick doubly drained layer of saturated clay under a surcharge loading underwent 90%…

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Q: A singly drained clay deposit 10 meters thick has a coefficient of consolidation of 2.0 x 10-4 cm2 /…

A: Given:Single drainedThickness = 10 m = (10*100) cmCoefficient of consolidation= 2*10-4 cm2/sUltimate…

Q: Laboratory tests on a 25 mm thick clay sample drained at the top and bottom show that 50%…

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Q: The figure below shows the soil profile at a site where you plan to lower the water table. You have…

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Q: 1.In an oedometer test a specimen of saturated clay 19 mm thick reaches 50% consolidation in 20 min.…

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Q: With the aid of sketches, explain Terzaghi's Spring Analogy Model.

A: Answer:- Terzaghi spring analogy model:- Terzahi showed that the consolidation process in a clay…

Unit Conversion

Standard units are also called SI units. SI units are used for measuring a physical quantity satisfying certain conditions. There are two types of units: fundamental units and derived units. Fundamental units are physical quantities that are independent, that is, they do not depend on other quantities like mass, length, or time. There are plenty of quantities in our lives which need to be measured and compared. Measuring is the comparison of a particular physical quantity with its reference value. A unit is a measure of a fixed physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.