a) In the situation illustrated above the mass m₁ is at rest initially. Show that the maximum possible value of the mass m₂ for which m₁ will not slip down the slope is given by m = m₁ (μ, cos sin 0). 0 - For a particular case, m₁ = 25 kg, 0 = 15°, Ms = 0.32 and μk = 0.16, where μk is the Mk coefficient of kinetic friction between the mass m₁ and the slope.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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0
m2
a)
In the situation illustrated above the mass
m₁ is at rest initially. Show that the
maximum possible value of the mass m₂
for which my will not slip down the slope
is given by m = m₁ (μs cos 0 - sin 0).
For a particular case, m₁ = 25 kg, 0 = 15°,
Ms = 0.32 and μk = 0.16, where μk is the
coefficient of kinetic friction between the
mass m₁ and the slope.
Transcribed Image Text:0 m2 a) In the situation illustrated above the mass m₁ is at rest initially. Show that the maximum possible value of the mass m₂ for which my will not slip down the slope is given by m = m₁ (μs cos 0 - sin 0). For a particular case, m₁ = 25 kg, 0 = 15°, Ms = 0.32 and μk = 0.16, where μk is the coefficient of kinetic friction between the mass m₁ and the slope.
b)
Calculate the acceleration of mass m₁
parallel to the slope when m₂ = 0.63 kg.
c)
Calculate the acceleration of mass m₁
parallel to the slope when m₂ = 2.9 kg.
Transcribed Image Text:b) Calculate the acceleration of mass m₁ parallel to the slope when m₂ = 0.63 kg. c) Calculate the acceleration of mass m₁ parallel to the slope when m₂ = 2.9 kg.
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