**Problem 75.** The initially stationary 20 kg block is subjected to the time-varying horizontal force whose magnitude $ P $ is shown in the plot. Note that the force is zero for all times greater than 3 s. Determine the time $ t_s $ at which the block comes to rest.In the diagram, a 20 kg block is shown with a horizontal force $ P $ being applied to it. The coefficients of friction are given as: $ \mu_k = 0.40 $ (kinetic friction) and $ \mu_s = 0.60 $ (static friction).The adjacent graph depicts the force $ P $ in newtons (N) versus time $ t $ in seconds (s). - The graph shows a linear increase of force $ P $ from 0 N at $ t = 0 $ to 150 N at $ t = 3 $ s.- After 3 s, the force $ P $ becomes 0 N and remains constant.

Given data:Mass is m=20 kg.To find:The total time for the given block to stop.The force is:

Problem 75. The initially stationary 20 kg block is subjected to the time-varying horizontal force whose magnitude P is shown in the plot. Note that the force is zero P, N for all times greater than 3 s. Determine the time to at which the block comes to rest. Mk = 0.40) Mg = 0.60 20 kg P 150 t, s

Problem 75. The initially stationary 20 kg block is subjected to the time-varying horizontal force whose magnitude P is shown in the plot. Note that the force is zero P, N for all times greater than 3 s. Determine the time to at which the block comes to rest. Mk = 0.40) Mg = 0.60 20 kg P 150 t, s

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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**Problem 75.** The initially stationary 20 kg block is subjected to the time-varying horizontal force whose magnitude $ P $ is shown in the plot. Note that the force is zero for all times greater than 3 s. Determine the time $ t_s $ at which the block comes to rest.

In the diagram, a 20 kg block is shown with a horizontal force $ P $ being applied to it. The coefficients of friction are given as: $ \mu_k = 0.40 $ (kinetic friction) and $ \mu_s = 0.60 $ (static friction).

The adjacent graph depicts the force $ P $ in newtons (N) versus time $ t $ in seconds (s).

- The graph shows a linear increase of force $ P $ from 0 N at $ t = 0 $ to 150 N at $ t = 3 $ s.
- After 3 s, the force $ P $ becomes 0 N and remains constant.

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