(a) Identify the null hypothesis and alternative hypothesis. O A. Ho: H#3.8 H:u= 3.8 O B. Ho: u= 3.9 OC. Ho: u53.8 H: u#3.9 Hi p> 3.8 O D. Ho: us3.9 H:u> 3.9 O E. Ho: >3.8 H:us3.8 OF. Ho: u>3.9 H: us3.9 (b) Identify the standardized test statistic. z= (Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 O B. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds. pounds. O C. Reject Ho- There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds. O D. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds.

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Chapter1: Starting With Matlab
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A nutritionist claims that the mean tuna consumption by a person is 3.9 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.8 pounds per year. Assume the population standard deviation is 1.08
pounds. At a = 0.04, can you reject the claim?
(a) Identify the null hypothesis and alternative hypothesis.
O A. Ho: H#3.8
H:p= 3.8
O B. Ho: H= 3.9
OC. Ho: u53.8
Ha: u#3.9
H: u> 3.8
O D. Ho: uS39
O E. Ho: >3.8
H: us3.8
OF. Ho: u> 3.9
H: p> 3.9
H: us3.9
(b) Identify the standardized test statistic.
z=(Round to two decimal places as needed.)
(c) Find the P-value.
(Round to three decimal places as needed.)
(d) Decide whether to reject or fail to reject the null hypothesis.
O A. Fail
reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9
O B. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds.
pounds
OC. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds.
O D. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9
pounds.
Transcribed Image Text:A nutritionist claims that the mean tuna consumption by a person is 3.9 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.8 pounds per year. Assume the population standard deviation is 1.08 pounds. At a = 0.04, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: H#3.8 H:p= 3.8 O B. Ho: H= 3.9 OC. Ho: u53.8 Ha: u#3.9 H: u> 3.8 O D. Ho: uS39 O E. Ho: >3.8 H: us3.8 OF. Ho: u> 3.9 H: p> 3.9 H: us3.9 (b) Identify the standardized test statistic. z=(Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 O B. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds. pounds OC. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds. O D. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.9 pounds.
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