A hypothesis will be used to test that a population mean equals 5 against the alternative that the population meanis less than 5 with unknown variance. What is the critical value for the test statistic To for the followingsignificance levels?Round your answers to three decimal places (e.g. 98.765).(a) a = 0.01 andn = 15.To =i(b) a = 0.05 and n = 7.Toi(c) a = 0.10 and n = 7.Toi

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Answered: A hypothesis will be used to test that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (H.) at a significance level of a= 0.05. H, µ = 84.3 Ha: > 84.3 (Claim) You believe the population is normally distrbuted, but you do not know the standard deviation. You obta a sample of size n= 115 with mean T= 88.8 and a standard deviation of s=13.4. a.) What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic b.) What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value (use Excel)
You wish to test the following claim (Ha) at a significance level of a=0.02. H0: u=83.9 Ha:u<83.9 You believe the population is normally distributed but you do not know the standard deviation. You obtain a sample of size n=119 with the meanM=79.4 and a standard deviation of SD=12.9. What is the test statistic foe this sample? What is the P value for this sample? The p value is less than or greater than a? This test statistic leads to a decision to: reject the null, accept the null, or fail to reject the null?
You wish to test the following claim (Ha) at a significance level of a = 0.01. Ho: H 63.6 На: и > 63.6 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 66.9 78.6 53.8 57.9 57 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =
A single question with sub-parts. Please answer all parts. I appreciate it :(
You wish to test the following claim (HaHa) at a significance level of 0.01. Ho:μ=54.7Ho:μ=54.7 Ha:μ>54.7Ha:μ>54.7 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=54 with mean M=58.7 and a standard deviation of SD=11.7 The test statistic is 2.512. What is the p-value for this sample?
1. Depression scores (1-100) for young women (20-40 years old) are assumed to be normally distributed with a mean of 75.5 within the population. A sample of 26 women were recruited to have their depression scores recorded and the mean score was 82, with a standard deviation of 12. Researchers want to know if the sample data reflects a population with mean score of 75.5. Using a significance level of 0.01, answer the following questions. (a) What statistical test should the researchers conduct? Why? Explain your answer. (b) State the hypotheses for this scenario. (c) Conduct a hypothesis test based on question 1(a) to determine what the researcher should conclude from this study. Give your answer to two decimal places. (d) Suppose you obtained several random samples each with n = 100 women and each time you obtained their depression scores. Is it reasonable to assume that the sample means of these samples xx are approximately Normally distributed even though the population distribution…
You wish to test the following claim (HaHa) at a significance level of α=0.05 Ho:μ=59.9 Ha:μ>59.9You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=93n=93 with mean M=62.6M=62.6 and a standard deviation of SD=9.4SD=9.4.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 59.9. There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 59.9. The sample data support the claim that the…
The manufacturer claims that your new car gets 24 mpg on the highway. You suspect that the mpg is less for your car. The 44 trips on the highway that you took averaged 22.3 mpg and the standard deviation for these 44 trips was 4.2 mpg. What can be concluded at the αα = 0.05 level of significance? For this study, we should use (t-test for population mean, z-test for population proportion) The null and alternative hypotheses would be: H0: (symbol) (symbol) ____ H1: (symbol) (symbol) ____ The test statistic (?,t,z) = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is (?, less than or equal to, more than) αα Based on this, we should (accept, reject, fail to reject) the null hypothesis. Thus, the final conclusion is that ... The data suggest that the sample mean is not significantly less than 24 at αα = 0.05, so there is statistically insignificant evidence to conclude…
Suppose you had obtained a test statistic of 2.45 (this is incorrect). What would the P-value be? Draw a conclusion based on a = 0.01. Select one: O a. 0.01 < P-value < 0.02, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O b. 0.005 < P-value < 0.01, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O c. 0.01 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O d. 0.005 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet…
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 14 samples is 4.9 ppm with a variance of 1.2 Does the data support the claim at the 0.01 level? Assume the population distribution is approximately normal. Step 2 of 5 : Find the value of the test statistic. Round your answer to three decimal places.
You wish to test the following claim (Ha) at a significance level of a = 0.02. H.:µ = 73.5 Ha:µ + 73.5 You believe the population is normally distributed, but you do not know the standard deviation. Your sample has: size: n = 61 mean: M = 76 standard deviation: SD = 18.1. What is the test statistic for this sample? (Round the answer accurate to 3 decimal places.) test statistic: t = What is the P-value for this sample? (Round the answer accurate to 3 decimal places.) P-value = The P-value is... less than (or equal to) a greater than a This leads to a decision to... reject the null accept the null fail to reject the null So, the final conclusion is that... O The data do not support the claim of the alternative hypothesis that the population mean is not equal to 73.5. The sample data support the claim of the alternative hypothesis that the population mean is not equal to 73.5.
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120

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