A hydrogen atom (m = 1.674 × 10-27 kg) is moving with a velocity of 1.1250 x 107 m/s. It collides elastically with a helium atom (m= 6.646 x 10-27 kg) at rest. After the collision, the hydrogen atom is found to be moving with a velocity of -6.724 x 106 m/s (in a direction opposite to its original motion). Find the velocity of the helium atom after the collision by applying conservation of momentum;
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- Two billiard balls of mass m (gr) collide with their oblique center. a) Find the post-collision velocity of the balls. b) Find the energy loss that will occur during the collision. m=170 kg V1= 3.3 m/s V2=2.8 m/s Ɵ 1=40 Ɵ 2=38 e=0.5One billiard ball (mass 118 grams) is moving due east at 5.0 m/s. A tennis ball (mass 321 grams) is moving due west at 4.0 m/s. The two balls have a glancing blow, which means they do not bounce along the same line as their original motion, but rather, deflect at an angle to their original paths. You measure the billard ball's motion as it moves 26.0° north of east, and you measure that the tennis ball is travelling 19.0° south of west. What is the speed of the billiard ball after the collision? Your Answer: AnswerA helium atom (m = 6.6465 x 10-27 kg) collides elastically with an oxygen atom (m = 2.6560 x 10-26 kg) at rest. After the collision, the helium atom is observed to be moving with a velocity of 6.636 x 106 m/s in a direction at an angle of 84.7 relative to its original direction. The oxygen atom is observed to move at an angle of -40.4° Find the speed of the oxygen atom
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- In a very busy off-campus eatery, one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter from left to right at 1.79 m/s. Almost simultaneously, the other chef launches a 335 g veggie burger (with everything, but hold the horseradish) along the same counter from right to left at 2.47 m/s. The two delicacies collide head-on at the given speeds. The counter is practically friction-free due to accumulated grease. The two delicacies merge into a single, unbelievably savory serving. In what direction does the merged meal move, if it moves at all? A) does not move B) to the right C) to the left At what speed does it move in m/s? Enter a positive number.Two 1.9 kg bodies, A and B, collide. The velocities before the collision are v A= (14î + 34 j) m/s and v = (-15î + 9.0j) m/s. After the collision, v = (-7.oî + 16 j) m/s. (a) What is the final velocity of B? m/s (b) What is the change in the total kinetic energy (including sign)? 121.69 J The net external force on the two particle system is zero; thus, the net momentum of the system cannot change. The net momentum along the x axis before the collision must equal that after the collision. Same for the y axis. Use the definition of kinetic energy to find the total K before the collision and the total K after.A mass of 2.71 kg is traveling in the +x direction with velocity 5.60 m/s. It collides with a stationary mass of 4.32 kg and the collision is elastic. What is the velocity of the 4.32 kg mass after the collision in m/s?
- Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved. Object A has a mass of mA = 17.9 kg and an initial velocity of VOA = 7.25 m/s, due east. Object B, however, has a mass of mg = 29.3 kg and an initial velocity of VOB = 4.41 m/s, due north. Find the (a) magnitude and (b) direction of the total momentum of the two-object system after the collision. (a) P₁ = Number i (b) 0 = Number i eTextbook and Media GO Tutorial Units Units north of eastA steel ball of mass 0.5 kg is fastened to a cord that is 70.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal. At the bottom of its path, the ball strikes a 2.5 kg steel block initially at rest on a frictionless surface. The collision is elastic. Find (a) the speed of the ball and (b) the speed of the block both just after the collision.