Consider a particle A of mass ma = 10 kg moving at a velocity t = 3 i +3 j m/s and a particle B of mass mg = 10 kg moving at a velocity Vg before collision. After collision, particle A is moving at a velocity i = -3 v2 i+ 3ĵ m/s and particle B is moving at a velocity vg = 3 i m/s. Calculate the the change in %3D = - 3 V2 i m/s the x-component of the linear momentum (in kg.m/s) of the set of particles during the collision. VB B. B. B.

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Chapter1: Units, Trigonometry. And Vectors
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Consider a particle A of mass ma = 10 kg moving at a velocity i = 3 i+3j
m/s and a particle B of mass mg = 10 kg moving at a velocity vg = - 3 v2 i m/s
before collision. After collision, particle A is moving at a velocity v = -3 V2 i +3 j
m/s and particle B is moving at a velocity uz = 3 i m/s. Calculate the the change in
the x-component of the linear momentum (in kg.m/s) of the set of particles during
the collision.
B
B.
Before Collision
During Collision
After Collision
Transcribed Image Text:Consider a particle A of mass ma = 10 kg moving at a velocity i = 3 i+3j m/s and a particle B of mass mg = 10 kg moving at a velocity vg = - 3 v2 i m/s before collision. After collision, particle A is moving at a velocity v = -3 V2 i +3 j m/s and particle B is moving at a velocity uz = 3 i m/s. Calculate the the change in the x-component of the linear momentum (in kg.m/s) of the set of particles during the collision. B B. Before Collision During Collision After Collision
Expert Solution
Step 1 To determine,

The change in the x-component of the linear momentum (in kgms-1).given,mA=10 kgvAi=3i^+3j^ ms-1mB=10 kgvBi=-32 i^ ms-1vAf=-32 i^+3j^ ms-1vBf=3i^ ms-1

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