A ball with mass mj = 1.21 kg is initially travelling to the right with a speed u = 4.12 m/s. It collides with a second ball with mass m2 = 2.13 kg, the second ball is initially at rest. After the collision, the ball with mass mj = 1.21 kg travels to the left with speed U1 = 0.743 m/s while the ball with mass m2 = 2.13 kg travels to the right. initial final V2 u m1 m2 m1 m2 Figure 1. Diagram of the collision of two balls. Part 1) What is the final speed of the ball with mass m2 = 2.13 kg? U2 = m/s Part 2) What is the change in the kinetic energy of the system during this collision? Give a positive answer if the final kinetic energy is greater than the initial kinetic energy. AK = K¡ – K¡ =

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A ball with mass m¡ =
1.21 kg is initially travelling to the right with a speed u = 4.12 m/s. It collides with a second ball with mass
m2 = 2.13 kg, the second ball is initially at rest. After the collision, the ball with mass m1 = 1.21 kg travels to the left with speed
v1 = 0.743 m/s while the ball with mass m2 = 2.13 kg travels to the right.
initial
final
V2
u
m1
m2
m1
m2
Figure 1. Diagram of the collision of two balls.
Part 1)
What is the final speed of the ball with mass m2 =
2.13 kg?
m/s
U2
Part 2)
What is the change in the kinetic energy of the system during this collision? Give a positive answer if the final kinetic energy is greater than
the initial kinetic energy.
AK = K¡ – K¡ =
Transcribed Image Text:A ball with mass m¡ = 1.21 kg is initially travelling to the right with a speed u = 4.12 m/s. It collides with a second ball with mass m2 = 2.13 kg, the second ball is initially at rest. After the collision, the ball with mass m1 = 1.21 kg travels to the left with speed v1 = 0.743 m/s while the ball with mass m2 = 2.13 kg travels to the right. initial final V2 u m1 m2 m1 m2 Figure 1. Diagram of the collision of two balls. Part 1) What is the final speed of the ball with mass m2 = 2.13 kg? m/s U2 Part 2) What is the change in the kinetic energy of the system during this collision? Give a positive answer if the final kinetic energy is greater than the initial kinetic energy. AK = K¡ – K¡ =
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