Two 1.9 kg bodies, A and B, collide. The velocities before the collision are V = (14î + 34 j) m/s and va = (-1si + 9.0j) m/s. After the collision, V = (-7.0î + 16 j) m/s. (a) What is the final velocity of B? m/s (b) What is the change in the total kinetic energy (including sign)? 121.69 The net external force on the two particle system is zero; thus, the net momentum of the system cannot change. The net momentum along the x axis before the collision must equal that

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Two 1.9 kg bodies, A and B, collide. The velocities before the collision are v
A= (14î + 34 j) m/s and v = (-15î + 9.0j) m/s. After the collision, v = (-7.oî + 16 j) m/s.
(a) What is the final velocity of B?
m/s
(b) What is the change in the total kinetic energy (including sign)?
121.69
J
The net external force on the two particle system is zero; thus, the net momentum of the system cannot change. The net momentum along the x axis before the collision must equal that
after the collision. Same for the y axis. Use the definition of kinetic energy to find the total K before the collision and the total K after.
Transcribed Image Text:Two 1.9 kg bodies, A and B, collide. The velocities before the collision are v A= (14î + 34 j) m/s and v = (-15î + 9.0j) m/s. After the collision, v = (-7.oî + 16 j) m/s. (a) What is the final velocity of B? m/s (b) What is the change in the total kinetic energy (including sign)? 121.69 J The net external force on the two particle system is zero; thus, the net momentum of the system cannot change. The net momentum along the x axis before the collision must equal that after the collision. Same for the y axis. Use the definition of kinetic energy to find the total K before the collision and the total K after.
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