Two rocks collide in outer space. Before the collision, one rock had mass 15 kg and velocity < 4300, -2700, 2600 > m/s. The other rock had mass 10 kg and velocity <-650, 2200, 3650 > m/s. A 1 kg chunk of the first rock breaks off and sticks to the second rock. After the collision the 14 kg rock has velocity < 1500, 350, 2000 >m/s. After the collision, what is the velocity of the other rock, whose mass is now 11 kg?Additional MaterialseBookm/s (a) Calculate the magnitude of the gravitational force exerted by Mars on a 65 kg human standing on the surface of Mars. (The mass of Mars is 6.4×1023 kg and itsradius is 3.4×106 m.)240.0277N(b) Calculate the magnitude of the gravitational force exerted by the human on Mars.240.0277N(c) For comparison, calculate the approximate magnitude of the gravitational force of this human on a similar human who is standing 2.5 meters away.1.76e8X N(d) What approximations or simplifying assumptions must you make in these calculations? (Note: Some of these choices are false because they are wrong physics!)✔ Treat Mars as though it were spherically symmetric.Ignore the effects of the Sun, which alters the gravitational force that one object exerts on another.✔ Treat the humans as though they were points or uniform-density spheres.Use the same gravitational constant in (a) and (b) despite its dependence on the size of the masses.Additional MaterialseBook

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Answered: Two rocks collide in outer space.…

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