A hot solution of Ba(NO3)2 from an evaporator contains 30.6 kg Ba(NO3)2 per 100 kg water and goes to a crystallizer, where the solution is cooled and Ba(NO3)2 crystallizes. On cooling, 10% of the original water present evaporates. For a feed solution of 100 kg total, calculate the following: a. The yield of crystals if the solution is cooled to 290 K (17°C), where the solubility is 8.6 kg Ba(NO3)2 per 100 kg water. b. The yield if cooled instead to 283 K, where the solubility is 7.0 kg Ba(NO3)2 per 100 kg water
A hot solution of Ba(NO3)2 from an evaporator contains 30.6 kg Ba(NO3)2 per 100 kg water and goes to a crystallizer, where the solution is cooled and Ba(NO3)2 crystallizes. On cooling, 10% of the original water present evaporates. For a feed solution of 100 kg total, calculate the following: a. The yield of crystals if the solution is cooled to 290 K (17°C), where the solubility is 8.6 kg Ba(NO3)2 per 100 kg water. b. The yield if cooled instead to 283 K, where the solubility is 7.0 kg Ba(NO3)2 per 100 kg water
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A hot solution of Ba(NO3)2 from an evaporator contains 30.6 kg Ba(NO3)2 per 100 kg water and goes to a crystallizer, where the solution is cooled and Ba(NO3)2 crystallizes. On cooling, 10% of the original water present evaporates. For a feed solution of 100 kg total, calculate the following:
a. The yield of crystals if the solution is cooled to 290 K (17°C), where the solubility is 8.6 kg Ba(NO3)2 per 100 kg water.
b. The yield if cooled instead to 283 K, where the solubility is 7.0 kg Ba(NO3)2 per 100 kg water
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