A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point)the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance d0.233 m from therock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight.If the homeowner can apply a maximum force of 703 N at the other end of the rod, what is the minimum total length L of the rodrequired to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner'sforce are both essentially vertical. The acceleration due to gravity is g9.81 m/s?.L = A young work crew is trying to quickly finish some touch-up painting to complete a job. Rather than setting up a secure work area,they decide to try a shortcut. Worker A will hold the far end of a 8.00 m work plank which weighs 115 N and is secured with ahinge on the opposite end. Worker B will stand on the plank 4.99 m from worker A. Worker B also brings up his paint can,m. =: 3.58 kg, which he places 0.250 m from where he is standing on the plank (between the two workers). Worker A unfortunatelyneeds to supply 509 N of force to hold the end of the plank. How much does worker B weigh? The acceleration due to gravityis g = 9.81 m/s².%3|weight of worker WB

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A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance d = 0.233 m from the rock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight. If the homeowner can apply a maximum force of 703 N at the other end of the rod, what is the minimum total length L of the rod required to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s². L = m

A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance d = 0.233 m from the rock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight. If the homeowner can apply a maximum force of 703 N at the other end of the rod, what is the minimum total length L of the rod required to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s². L = m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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