A hollow circular torsion member has an outside diameter of 22 mm and inside diameter of 18 mm, with mean diameter D = 20 mm and t/D=0.10. Calculate the torque and angle of twist per unit length if shearing stress at mean diameter is 70 MPa. Calculate these values if a cut is made through the wall thickness along the entire length G = 77.5 GPa.

Q: 3) A cantilevered bar has a circular cross section with 15-mm diameter and shear modulus of G = 26…

A: The diameter of circular cross section is .The shear modulus is .The torque is The length of the bar…

Q: A hollow aluminium tube used in a roof structure has an outside diameter 104mm and an inside…

A: A) Angle of twist for the given max shear stress in a hollow shaft: The angle of twist of a hollow…

Q: A thin-walled tube is subjected to torsion as shown. Determine the angle of twist produced. (in rad)

A: Given Radius =300 mm = 0.3 m Length = 6 m Thickness = 25 mm = 0.025 m T = 4kN m = 4000 Nm G = 70 GPa…

Q: The maximum value of the torsional shear stress is kpsi.

A: To find Torsional shear stress

Q: A solid steel shaft must not twist through more than 30 in a 6-m length when subjected to a torque…

A:

Q: A shaft consisting of an aluminum segment and a steel segment is acted upon by two torques. The…

A: The diameter of the aluminum section is The diameter of steel section is  The shear modulus of…

Q: Problem 5

A:

Q: a solid rod with a circular cross-secton is subject to a torque of 253 N.m. if diameter of the rod…

A:

Q: A hollow tube extruded with the shape of an equilateral triangle is shown in the figure below. Its…

A: Given: Length of the tube→L=56 in Length of the base→d=2 in Thickness of the wall→t=0.12 in Hence…

Q: Answer number 2 Good handwriting

A: Established the relation among two stresses as follows.

Q: An irregular shaped hollow tube, with the dimensions shown in figure below, is subjected to a torque…

A: Given: The torque→T=2.5 kN.m Length of the tube→L=4 m Wall thickness of the vertical side→t1=6…

Q: 2) An idealized free-body diagram of a door handle is shown below. To simplify, member X-Y is only…

A: Given: Let us consider the given data, M=1500×0.100=150 NmT=1500×0.2=300 Nmdiameter,d=20 mm=bσ= 3MPa

Q: TUATION 2: Find the smallest diameter of bolt and the minimum thickness of each yoke that on be used…

A:

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.