An irregular shaped hollow tube, with the dimensions shown in figure below, is subjected to a torque of2.5 kN m. If the tube is fabricated from steel and is 4 m long, determine the maximum value of the averageshearing stress and the angle of twist of the tube. Note that the wall thickness of vertical sides is 6 mm and thethickness of the horizontal sides is 5 mm.*Assume the following values:• L₁= 44 mm• L₂ = 50 mm• L3= 88 mm• LA = 25 mmTaug++ S+O- L₁number (rtol-0.01, atol-1e-05)number (rtol-0.01, atol-1e-05)L3MPaL2

Given: The torque→T=2.5 kN.m Length of the tube→L=4 m Wall thickness of the vertical side→t1=6…

Answered: An irregular shaped hollow tube, with…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

An irregular shaped hollow tube, with the dimensions shown in figure below, is subjected to a torque of
2.5 kN m. If the tube is fabricated from steel and is 4 m long, determine the maximum value of the average
shearing stress and the angle of twist of the tube. Note that the wall thickness of vertical sides is 6 mm and the
thickness of the horizontal sides is 5 mm.
*
Assume the following values:
• L₁= 44 mm
• L₂ = 50 mm
• L3= 88 mm
• LA = 25 mm
Taug
++ S+
O
- L₁
number (rtol-0.01, atol-1e-05)
number (rtol-0.01, atol-1e-05)
L3
MPa
L2

Expert Solution

Step 1

Given:

The torque $\to T = 2.5 k N . m$

Length of the tube $\to L = 4 m$

Wall thickness of the vertical side $\to t_{1} = 6 m m = 0.006 m$

Thickness of the horizontal side $\to t_{2} = 5 m m = 0.005 m = t_{m i n}$

Because mean line area of the cross section:

$\to A_{o} = (L_{4} - t_{2}) \times L_{1} + (L_{3} - L_{1} - t_{1}) \times (L_{2} - t_{2}) = (25 - 5) \times 44 + (88 - 44 - 6) \times (50 - 5) = 2590 m m^{2} = 0.00259 m^{2}$

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