A hard water sample was found to have an equivalent of 0.1598 g CaCO3 (mw =100g/mol). What volume of 0.05M EDTA would be required to remove the calcium from the water sample?

Q: You decide to measure the concentration of Ca^2+ in a glass of tap water with a complexometric…

A: The concentration of EDTA is; EDTA=mEDTAMMEDTA×V1.0 L=4.25 g336.2063 g/mol×50.00 mL×1000 mL1.0…

Q: A 100.0 ml. solution of 0.0200 M Fe³* in I M HCIO, is titrated with 0.100 M Cu*, resulting in the…

A: Given that, a 100.0 mL solution of 0.0200 M Fe3+ in 1 M HClO4 is titrated with 0.100 M Cu+,…

Q: after dissolving in 50.0 ml of good water, the zinc in a 0.3232 gram sample of foot powder was…

A: The percentage of Zn can be calculated asThe weight of zinc = 0.3232 gramsMolar mass of Zn2P2O7 =…

Q: Calculate the volume of 0.0477 M EDTA needed to titrate the Ca in a 0.1715 g CaCO, (MM = 100.0869…

A: Ca2+ forms a 1:1 complex with EDTA  Zn2+ also forms a 1:1 complex with EDTA  So, 1 mole of Ca2+ or 1…

Q: You are given a 1 M MgSO4 solution and a 0.5 M EDTA solution. Calculate how to make a 250 mL…

A: MgSO4 = 6.25 ml EDTA = 0.50 ml  Water = 243.25 ml

Q: 6mL of 125mM EDTA was added to 244mL of water.  The resulting solution was added to 219mL of water…

A: MW of EDTA =292.24 g  initial molarity of EDTA = 125mM

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A: The balanced ionic equation for the reaction between potassium oxalate and potassium permanganate…

Q: A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol)…

A:

Q: The concentration of CA2+ in an unknown solution was determined by titration with the EDTA solution…

A: Molarity of EDTA solution = 0.000085 M Volume of EDTA solution = 35.54 mL Volume of the diluted…

Q: A 49.10 mL aliquot from a 0.500 L solution that contains 0.530 g of MnSO4 (MW=151.00 g/mol) required…

A: Solution -

Q: A 1.000-g sample containing KHC204, H2C204, and impurities required 38.22 mL of 0.1000 M NaOH for…

A: The answer is 1.582 m moles of KHC2O4

Q: For the complexometric titration

A: The method uses a very large molecule called EDTA which forms a complex with calcium ions. EDTA…

Q: If you have a sample of 100 mg/L of calcium, and you have two standardized EDTA solutions of 0.005 M…

A: the balanced equation for the reaction between EDTA and Ca is  Ca+2 + EDTA–4 ----------->…

Q: An unknown Ca solution was prepared by weighing a 2.122 g sample, dissolving it in HCl and then…

A:

Q: How much 0.0500 M EDTA is needed to titrate the Mg and Ca in a 0.2385-g sample that is 92.5%…

A: Given,  Molarity of EDTA = 0.0500 M  Mass of the sample = 0.2385 g  Mass percent of dolomite = 92.5%…

Q: 20. Assume you are using 0.1 M EDTA to titrate a 0.2 M Ca* solution (25 mL) at pH 10.0. V molarity…

A: Calculation of no. of mol of Ca2+: n=Molarity×Volume=0.2 mol/L×25×10-3 L=5×10-3 mol Calculation of…

Q: Given 100 mL of a solution that contains 0.80 mM Ag* and 0.80 mM Cu*, can the two metals be separat…

A: The solution to be separated has: [Ag+(aq)] = 0.80 mM or 8.0*10-4 M  [Cu+(aq)] = 0.80 mM or 8.0*10-4…

Q: 50.00 ml of a 0.0500 M Ni2+ solution, whose pH is adjusted to pH=11 and the solution is additionally…

A: The titration of 50.00 mL solution of 0.0500 M Ni2+ is carried out with 0.100 M EDTA solution while…

Q: A solution is prepared by mixed 50.0 mL of 0.0400 M Ni2+ with 50.00 mL of 0.0400 M EDTA. Calculate…

A: The objective of this question is to calculate the concentration of Ni2+ when a solution is prepared…

Q: Noting the curved arrows, draw all the product(s), organic and inorganic, of the following reaction.…

A: In an organic reaction mechanism, a curved arrow represents the transfer of electrons. In an organic…

Q: 47.6 mL aliquot from a 0.5 L solution that contains 0.45g of MnSO4 (MW is 151 g/mol) required 41.9…

A:

Q: 50.00 mL of a solution containing both Ni2* and Pb²+ ions requires 46.32 ml of a 0.02041 M EDTA…

A:

Q: In complexation volumetry, classify the statements below as true or false. Justify the one(s) that…

A: EDTA i.e. Ethylenediaminetetraacetic acid is a well known metal-chelating agent, it is hexadentate…

Q: How much free lead (II) ion is present in a 95.4 mL of a solution that contains 136.8 microgram of…

A: Answer: Higher the formation constant, more stable will be the compound. The value of high stability…

Q: 0.7682 g MgCO3 is dissolved in 1000 mL water, 50 mL of this solution is taken and titrated with…

A: • Since, here is given that MgCO3 is taken as 0.7682 gm and its aqueous solution has been made in…

Q: Calculate the concentration of Fe2O3 in a mineral sample after solubilization of 0.4891g and…

A: from the reaction, 6 mole Fe2+ react with 1 mole K2Cr2O7. mole = mass  molar mass

Q: Consider the titration of 25.00 mL of 0.03555 M Co2+ by 0.02784 M EDTA at pH 10.00. Kf is 1045.…

A: The amount of EDTA required to reach the endpoint of the titration is determined as shown below.…

Q: In a redox titration, 20ml of completely oxidised by 12.5ml of 0.02mol/L acidified Fe(II)SO4 was

A: 1) In acidic medium K2Cr2O7 is OA (reduced)  and converts into Cr+3 ions  FeSO4 is RA (oxidized)…

Q: The landfill manager suggested using HI with NaI as a buffer to minimize pH changes. Do you agree…

A: A buffer solution is a solution whose pH does not change by adding small amount of acid and base.

Q: What will be the pH if 5.00 grams of solid KOH is added to 500 mL of a solution containing 0.020…

A: Since you have posted 2 completely unrelated questions, we are entitled to answer only the first.

Q: Calculate the volume of 0.0602 M EDTA needed to titrate 11.63 mL of 0.0725 M Mg(NO3)2.

A:

Q: A 47.90 mL aliquot from a 0.500 L solution that contains 0.480 g of MnSO4 (MW= 151.00 g/mol)…

A: The objective of the question is to determine the mass of calcium carbonate.

Q: 0.7682 g MgCO3 is dissolved in 1000 mL water, 50 mL of this solution is taken and titrated with…

A:

Q: A 3.25 g sample of an iron-containing mineral was dissolved in an acid medium and calibrated to 500…

A: This problem is based on analytical chemistry. Here we shall find the amount of Fe3+ in the sample.…

Q: As part of a geological team that studied a local cave, you brought with you a bunch of 1.00 g rock…

A: Given that -  Mass of sample of rock = 1.00 g  Molarity of EDTA Solution used = 0.050 M  Volume of…

Q: The Zn in a 0.6803-g sample of foot powder was titrated with 27.3 mL of 0.04246 M EDTA. Calculate…

A: To calculate the percentage of zinc in the foot powder sample, use the EDTA titration. First…

Q: Given that the formation constant for Ca^2+ i2 10^10.65 and aY^4- =0.30 at a pH of 10.00. 1.How…

A: The question is based on the concept of complexometric titrations. we have to explain the impact of…

Q: A 46.4046.40 mL aliquot from a 0.4850.485 L solution that contains 0.3500.350 g of MnSO4MnSO4…

A: [(0.450 g MgSO4 ) / (120.37 g MgSO4 /mol)] x [(0.0500 L / 0.5000 L) ÷ (0.0376 L EDTA)] x [(1 mol…

Q: Titration of I 2 produced from 0.1500 g of primary-standard-grade KIO 3 required 42.30 mL of sodium…

A: Answer is explained below.  Ans: The concentration of the Na2S2O3 is 0.099 M.

Q: what is the value of magnesium in ppm in the sample?(Mg:24 g/mol)

A: The titration reaction is: Mg2+ + EDTA-4 ====> Mg(EDTA)-2 Let us first calculate moles of EDTA…

Q: In the determination of Ca2+ in milk powder, 12.1 mL 0.01 M EDTA is used for 1.50 grams of sample.…

A:

Q: A 0.2500 g sample containing calcium carbonate spends 40.00 mL of a 1 M EDTA solution. Calculate the…

A: We must ascertain the volume of calcium carbonate (CaCO3) in the 0.2500 g sample and convert it to a…

Q: The concentration of yeast RNA in an aqueous solution is 12.0 mg/L. The absorbance is found to be…

A: Absorbance is given by the formula A = εbC A = absorbance ε = molar absobptivity b = length of light…