A Hall probe serves to measure magnetic field strength. One such probe consists of a poor conductor 0.121 mm thick, whose charge‑carrier density is 1.27×1025⁢ m−3. When a 1.77 A current flows through the probe, the Hall voltage is measured to be 3.15 mV. The elementary charge e=1.602×10−19 C. What is the magnetic field strength B?

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Q: An electron in J. J. Thomson's charge-to-mass apparatus moves perpendicular to a B-field along a…

A: Radius circular path: r = 13.10 cm = 0.1310 m Magnitude of electric field: E = 17.80 kV/m = 17800…

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A: Charge of the particle (q)=6.408×10-19 C Mass of the particle (m)=2.34×10-26 kg Distance of particle…

Q: A mass spectrometer (see figure below) operates with a uniform magnetic field of 21.0 mT and an…

A: Magnetic field B = 21.0 mT = 0.021 T Electric field E = 3.55 ✕ 103  V/m Mass of alpha particle ma =…

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A: distance between two wires (d) = 5 cm = 0.05 m current in each of two parallel wires (I) = 1.2 A

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A: Given: A proton is moving in crossed electric and magnetic field without changing its velocity.…

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A: Given that: L=1.80 mR=0.75ΩV=12.0 VF=125 N

Q: The figure below shows a mass spectrometer. Particles with charge -e = -1.60×10¬19 C enter a…

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A: Current I=5 A Distance, d=0.4 cm = 0.004 m Charge, q=1 C Velocity, v=1.9 m/s

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Q: A 15 mC charge has a velocity of m/s and is moving in a magnetic field T. What is the magnetic…

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Q: Two parallel wires, separated by a perpendicular distance of 5.0 cm, carry currents of 5.0 A and 2.0…

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Q: A Hall probe serves to measure magnetic field strength. One such probe consists of a poor conductor…

A: Given that              The thickness of the conductor is (d) = 0.135mm               Charge…

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A: It is given that the kinetic energy of two particles. K10eV=10eVK10keV=10 keV

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A: Write the given values with the suitable variables. L=2 mm=342 g=0.342 kgB=1.9 T Here, L, m, and B…

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A: laser  emits 10-ns-long pulses of light,  energy=2.5mJ, the laser is focused to a…

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A: Using Work energy theorem The change in the kinetic energy of the particle is equal to net work done…

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A: Using electric and magnetic field concepts the problem can be solved

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Q: A wire has a current of 45 A going into the page. What is the B field and direction 1.5 m to the…

A: current = i = 45 A distance = r = 1.5 m speed of proton = V = 5 m/s

Q: The magnetic field of a proton is approximately like that of a circular current loop 0.650 × 10-15 m…

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Q: A particle with a charge of -1.24x10-8 C is moving with instantaneous velocity = (4.19×10¹ m/s)i +…

A: Given data :  Charge on particle q = -1.24 × 10-8 C  Velocity of charge particle v = (4.19 × 104…

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Q: A copper wire carries a current of 135 A to an electroplating tank. Find the magnetic field caused…

A: 1) current (I) = 135 A length (dl) = 1.3 cm = 0.013 m distance of point (d) = 1.5 mθ = 40o

Q: A charge of -8.84 μC is traveling at a speed of 6.02 × 106 m/s in a region of space where there is a…

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Q: In unit vector notation, find the magnetic force on the electron due to the current passing through…

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Q: A 4.3-MeV (kinetic energy) proton enters a 0.21-T field, in a plane perpendicular to the field.…

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Q: A charged particle is introduced into a uniform magnetic field Bz = 0.5 mTesla with an initial…

A: mv2r=qvBqm=vBr=1×106 m/s0.5 mT10-3 T1 mT2.4 cm10-2 m1 cm=0.833×1011 C/kg

Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.