A guitar string is vibrating in its fundamental mode, with nodes at each end. The length of thesegment of the string that is free to vibrate is 0.380 m. The maximum transverse acceleration of apoint at the middle of the segment is 8500 m/s² and the maximum transverse velocity is 3.40 m/s.Part AWhat is the amplitude of this standing wave?Express your answer in meters.A =ΜΕ ΑΣΦSubmitRequest AnswerPart B?mWhat is the wave speed for the transverse traveling waves on this string?Express your answer in meters per second.v =ΜΕ ΑΣΦSubmitRequest AnswerProvide Feedback?m/sReview | ConstantsNext >

Step 1:Length of the string is 0.38mAcceleration is 8500s2mVelocity is 3.4s2mStep 2:a)The…

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