Part A Two steel guitar strings A and B have the same length and are under the same tension. String A has a diameter of 0.65 mm and string B has a diameter 1.17 mm. Treat the stretched-out strings as right cylinders with length L and radius r having volume nFL You may assume that both strings are made of the same material, so they have the same density. The ratio of the wave speeds, Va/, in the two strings is (enter your answer with two significant figures) possibly usefut density = massvolume string fixed at both ends: A 2Un ;n= 1, 2, 3, 4, 5.. Vsquareroot|F/u] H- mass per unit length O RI ? Submit Bequest Answer • Part B The ratio of the eleventh harmonic trequency of string A to the eleventh harmonic trequency of string B. (lA/e- is (enter your answer with two significant figures) Submit Bequest Answer • Part C The ratio of the eighth harmonic frequency of string A to the fourth harmonic trequency of string B, (tale, is (enter your answer with three significant figures)

icon
Related questions
Question
Part A
Two steel guitar strings A and B have the same length and are under the same tension. String A has a diameter of 0.65 mm and string B has a diameter 1.17 mm. Treat the stretched-out strings as right cylinders with length L and radius r having volume rrL. You may assume that both
strings are made of the same material, so they have the same density. The ratio of the wave speeds, VA/VB, in the two strings is (enter your answer with two significant figures)
possibly useful.
density = mass/volume
V = AM
string fixed at both ends: An = 2L/n; n = 1, 2, 3, 4, 5...
v = squareroot(F/u]
H= mass per unit length
Submit
Request Answer
Part B
The ratio of the eleventh harmonic frequency of string A to the eleventh harmonic frequency of string B, (f1)A/(11)B, is (enter your answer with two significant figures)
Submit
Request Answer
Part C
The ratio of the eighth harmonic frequency of string A to the fourth harmonic frequency of string B, (fg)A/(f4)B, is (enter your answer with three significant figures)
?
Submit
Roguest Answer
Transcribed Image Text:Part A Two steel guitar strings A and B have the same length and are under the same tension. String A has a diameter of 0.65 mm and string B has a diameter 1.17 mm. Treat the stretched-out strings as right cylinders with length L and radius r having volume rrL. You may assume that both strings are made of the same material, so they have the same density. The ratio of the wave speeds, VA/VB, in the two strings is (enter your answer with two significant figures) possibly useful. density = mass/volume V = AM string fixed at both ends: An = 2L/n; n = 1, 2, 3, 4, 5... v = squareroot(F/u] H= mass per unit length Submit Request Answer Part B The ratio of the eleventh harmonic frequency of string A to the eleventh harmonic frequency of string B, (f1)A/(11)B, is (enter your answer with two significant figures) Submit Request Answer Part C The ratio of the eighth harmonic frequency of string A to the fourth harmonic frequency of string B, (fg)A/(f4)B, is (enter your answer with three significant figures) ? Submit Roguest Answer
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 5 steps

Blurred answer