A guitar string is vibrating in its fundam ental mode,with nodes at each end. The length of the segmentof the string that is free to vibrate is 0.389 m. Themaximum transverse acceleration of a point at themiddle of the segment is 8200 m/s? and themaximum transverse velocity is 3.10 m/s.Part AWhat is the amplitude of this standing wave?Express your answer in meters.Πνα ΑΣφA =mSubmitRequest AnswerPart BWhat is the wave speed for the transverse traveling waves on this string?Express your answer in meters per second.v =m/sSubmitRequest Answer

Given: a_max= 8200 m/s^2 V_max= 3.1 m/s a) Now Angular frequency ω=amaxvmax ω=82003.1 w =…

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