To practice Problem-Solving Strategy 15.2 Standing Waves. In lab, your instructor generates a standing wave using a thin string of length L = 2.25 m fixed at both ends. You are told that the standing wave is produced by the superposition of traveling and reflected waves, where the incident traveling waves propagate in the +x direction with an amplitude A = 3.85 mm and a speed vx 12.5 m/s. The first antinode of the standing wave is a distance of x = 37.5 cm from the left end of the string, while a light bead is placed a distance of 18.8 cm to the right of the first antinode. What is the maximum transverse speed vy of the bead? Make sure to use consistent distance units in your calculations. EXECUTE the solution as follows Part C What is the maximum transverse speed vy of the bead? Express your answer in meters per second. ▸ View Available Hint(s) Vy = 0.285 m/s Submit Previous Answers Correct EVALUATE your answer

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To practice Problem-Solving Strategy 15.2 Standing
Waves.
In lab, your instructor generates a standing wave
using a thin string of length L = 2.25 m fixed at both
ends. You are told that the standing wave is produced
by the superposition of traveling and reflected waves,
where the incident traveling waves propagate in the
+x direction with an amplitude A = 3.85 mm and a
speed vx = 12.5 m/s. The first antinode of the
standing wave is a distance of x = 37.5 cm from the
left end of the string, while a light bead is placed a
distance of 18.8 cm to the right of the first antinode.
What is the maximum transverse speed vy of the
bead? Make sure to use consistent distance units in
your calculations.
EXECUTE the solution as follows
Part C
What is the maximum transverse speed vy of the bead?
Express your answer in meters per second.
▸ View Available Hint(s)
Vy = 0.285 m/s
Submit
Previous Answers
Correct
EVALUATE your answer
Part D
To check your equation for the standing wave's transverse velocity, find the maximum transverse velocity at x = 75.0 cm.
Express your answer in meters per second.
Vy =
跖
ΜΠΙ ΑΣΦ
?
m/s
Transcribed Image Text:To practice Problem-Solving Strategy 15.2 Standing Waves. In lab, your instructor generates a standing wave using a thin string of length L = 2.25 m fixed at both ends. You are told that the standing wave is produced by the superposition of traveling and reflected waves, where the incident traveling waves propagate in the +x direction with an amplitude A = 3.85 mm and a speed vx = 12.5 m/s. The first antinode of the standing wave is a distance of x = 37.5 cm from the left end of the string, while a light bead is placed a distance of 18.8 cm to the right of the first antinode. What is the maximum transverse speed vy of the bead? Make sure to use consistent distance units in your calculations. EXECUTE the solution as follows Part C What is the maximum transverse speed vy of the bead? Express your answer in meters per second. ▸ View Available Hint(s) Vy = 0.285 m/s Submit Previous Answers Correct EVALUATE your answer Part D To check your equation for the standing wave's transverse velocity, find the maximum transverse velocity at x = 75.0 cm. Express your answer in meters per second. Vy = 跖 ΜΠΙ ΑΣΦ ? m/s
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