A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.20 km/s in the +x-direction experiences a force of 2.06x10-16 N in the +y-direction, and an electron moving at 4.70 km/s in the -z-direction experiences a force of 8.40x10-16 N in the +y-direction. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. Part A What is the magnitude of the magnetic field? Express your answer in teslas.
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.20 km/s in the +x-direction experiences a force of 2.06x10-16 N in the +y-direction, and an electron moving at 4.70 km/s in the -z-direction experiences a force of 8.40x10-16 N in the +y-direction. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. Part A What is the magnitude of the magnetic field? Express your answer in teslas.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:**Part B**
**Question:**
What is the direction of the magnetic field? (in the xz-plane)
**Instruction:**
Express your answer in degrees.
**Input Field:**
θ = 43.8°
(from the -z-direction to the +x-direction)
**Feedback:**
Incorrect; Try Again; 5 attempts remaining
---
**Part C**
**Question:**
What is the magnitude of the magnetic force on an electron moving in the -y-direction at 3.70 km/s?
**Instruction:**
Express your answer in newtons.
**Input Field:**
F = ____ N
---
**Part D**
**Question:**
What is the direction of the magnetic force? (in the xz-plane)
**Instruction:**
Express your answer in degrees.
**Input Field:**
θ = ____°
(from the -x-direction to the -z-direction)
.
#### Part A
**Question:** What is the magnitude of the magnetic field?
**Instruction:** Express your answer in teslas.
**Solution Box:**
\[ B = \underline{\hspace{3cm}} \, \text{T} \]
**User Attempt:**
\[ B = 1.1569 \, \text{T} \]
**Submission Status:**
Incorrect; Try Again. 5 attempts remaining.
#### Explanation
This problem involves using the magnetic force formula:
\[ F = qvB \sin \theta \]
Where:
- \( F \) is the force experienced by the particle.
- \( q \) is the charge of the particle.
- \( v \) is the velocity of the particle.
- \( B \) is the magnitude of the magnetic field.
- \( \theta \) is the angle between the velocity and the magnetic field direction.
To solve for \( B \), you may need to consider both the proton and the electron scenarios to determine the magnitude correctly.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa9a6cceb-4061-4ebd-82f8-5c7013e46e25%2F764ba4cd-1062-434b-9f4e-c15c9a0a90dd%2Fwtrurqk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Exercise 27.7 - Enhanced - with Solution
#### Problem Statement
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.20 km/s in the \( +x \)-direction experiences a force of \( 2.06 \times 10^{-16} \) N in the \( +y \)-direction. An electron moving at 4.70 km/s in the \( -z \)-direction experiences a force of \( 8.40 \times 10^{-16} \) N in the \( +y \)-direction.
For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of [Magnetic force on a proton](#).
#### Part A
**Question:** What is the magnitude of the magnetic field?
**Instruction:** Express your answer in teslas.
**Solution Box:**
\[ B = \underline{\hspace{3cm}} \, \text{T} \]
**User Attempt:**
\[ B = 1.1569 \, \text{T} \]
**Submission Status:**
Incorrect; Try Again. 5 attempts remaining.
#### Explanation
This problem involves using the magnetic force formula:
\[ F = qvB \sin \theta \]
Where:
- \( F \) is the force experienced by the particle.
- \( q \) is the charge of the particle.
- \( v \) is the velocity of the particle.
- \( B \) is the magnitude of the magnetic field.
- \( \theta \) is the angle between the velocity and the magnetic field direction.
To solve for \( B \), you may need to consider both the proton and the electron scenarios to determine the magnitude correctly.
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