A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.20 km/s in the +x-direction experiences a force of 2.06x10-16 N in the +y-direction, and an electron moving at 4.70 km/s in the -z-direction experiences a force of 8.40x10-16 N in the +y-direction. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. Part A What is the magnitude of the magnetic field? Express your answer in teslas.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Part B**

**Question:**  
What is the direction of the magnetic field? (in the xz-plane)

**Instruction:**  
Express your answer in degrees.

**Input Field:**  
θ = 43.8°  
(from the -z-direction to the +x-direction)

**Feedback:**  
Incorrect; Try Again; 5 attempts remaining

---

**Part C**

**Question:**  
What is the magnitude of the magnetic force on an electron moving in the -y-direction at 3.70 km/s?

**Instruction:**  
Express your answer in newtons.

**Input Field:**  
F = ____ N

---

**Part D**

**Question:**  
What is the direction of the magnetic force? (in the xz-plane)

**Instruction:**  
Express your answer in degrees.

**Input Field:**  
θ = ____°  
(from the -x-direction to the -z-direction)
Transcribed Image Text:**Part B** **Question:** What is the direction of the magnetic field? (in the xz-plane) **Instruction:** Express your answer in degrees. **Input Field:** θ = 43.8° (from the -z-direction to the +x-direction) **Feedback:** Incorrect; Try Again; 5 attempts remaining --- **Part C** **Question:** What is the magnitude of the magnetic force on an electron moving in the -y-direction at 3.70 km/s? **Instruction:** Express your answer in newtons. **Input Field:** F = ____ N --- **Part D** **Question:** What is the direction of the magnetic force? (in the xz-plane) **Instruction:** Express your answer in degrees. **Input Field:** θ = ____° (from the -x-direction to the -z-direction)
### Exercise 27.7 - Enhanced - with Solution

#### Problem Statement
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.20 km/s in the \( +x \)-direction experiences a force of \( 2.06 \times 10^{-16} \) N in the \( +y \)-direction. An electron moving at 4.70 km/s in the \( -z \)-direction experiences a force of \( 8.40 \times 10^{-16} \) N in the \( +y \)-direction.

For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of [Magnetic force on a proton](#).

#### Part A
**Question:** What is the magnitude of the magnetic field?  
**Instruction:** Express your answer in teslas.

**Solution Box:**
\[ B = \underline{\hspace{3cm}} \, \text{T} \]

**User Attempt:**
\[ B = 1.1569 \, \text{T} \]

**Submission Status:**
Incorrect; Try Again. 5 attempts remaining.

#### Explanation
This problem involves using the magnetic force formula:
\[ F = qvB \sin \theta \]

Where:
- \( F \) is the force experienced by the particle.
- \( q \) is the charge of the particle.
- \( v \) is the velocity of the particle.
- \( B \) is the magnitude of the magnetic field.
- \( \theta \) is the angle between the velocity and the magnetic field direction.

To solve for \( B \), you may need to consider both the proton and the electron scenarios to determine the magnitude correctly.
Transcribed Image Text:### Exercise 27.7 - Enhanced - with Solution #### Problem Statement A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.20 km/s in the \( +x \)-direction experiences a force of \( 2.06 \times 10^{-16} \) N in the \( +y \)-direction. An electron moving at 4.70 km/s in the \( -z \)-direction experiences a force of \( 8.40 \times 10^{-16} \) N in the \( +y \)-direction. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of [Magnetic force on a proton](#). #### Part A **Question:** What is the magnitude of the magnetic field? **Instruction:** Express your answer in teslas. **Solution Box:** \[ B = \underline{\hspace{3cm}} \, \text{T} \] **User Attempt:** \[ B = 1.1569 \, \text{T} \] **Submission Status:** Incorrect; Try Again. 5 attempts remaining. #### Explanation This problem involves using the magnetic force formula: \[ F = qvB \sin \theta \] Where: - \( F \) is the force experienced by the particle. - \( q \) is the charge of the particle. - \( v \) is the velocity of the particle. - \( B \) is the magnitude of the magnetic field. - \( \theta \) is the angle between the velocity and the magnetic field direction. To solve for \( B \), you may need to consider both the proton and the electron scenarios to determine the magnitude correctly.
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