A graduate student is performing a study on a new antidepressant. The drug is supposed to reduce depression, but the graduate student realizes that it may do nothing or even increase depression, so she decides to formulate nondirectional hypotheses and conduct a two-tailed test. She knows that the average score for all depressed people Is po = 25, with a standard deviation of a = 6. If she designates the mean for the population of depressed people who take the antidepressant aN Partdeprussante she can identify the null and alternative hypotheses as: Hot Panupressnt Po Ha Hentidnprennant * 10 The sample of 36 depressad people who tried out the new antideoressant scored an average of 23.3. Since the graduate student knows the standard devlation of the scores on the dearession inventory for the population of people who are depressed, she intends to use a hypothesis test that uses the z-score of the sample mean es the test statistic (also knawn as the z test). First, she wants to make sure all the required assumptions are satisfied. Which of the following conditions is not a required assumption for the z test? O Each observation is independent of every other observation. O The sampling distribution of M foilows a normal distribution. O Members of the samiple are selected randomly. The mean of the scores on the deprassion inventory is the same for those who take the antidepressant and those who don't. O The standard deviation of the scores on the depression inventory, is the same for those who take the antidepressant and those who don't. Use the Distributions tool to firid the critical region for o 05. Use the Distributions tool to find the critical region for a = ,05. Standard Normel Distribution Mean- 0.0 Standard Deviation1.0 5000 1500 a500 0.674 8.574 The critical z-scores (the values for z-scores that separate the tails from the main body of the distribution, forming the critical regions) are 12.326 Calculate the z statistic, and use the Distributions tool to evaluate the null hypothesis, The z statistic is-245 The z statistic does not lie in the critical region for a two-tailed hypothesis test. Therefore, the nul hypothesis is not rejected does does not
A graduate student is performing a study on a new antidepressant. The drug is supposed to reduce depression, but the graduate student realizes that it may do nothing or even increase depression, so she decides to formulate nondirectional hypotheses and conduct a two-tailed test. She knows that the average score for all depressed people Is po = 25, with a standard deviation of a = 6. If she designates the mean for the population of depressed people who take the antidepressant aN Partdeprussante she can identify the null and alternative hypotheses as: Hot Panupressnt Po Ha Hentidnprennant * 10 The sample of 36 depressad people who tried out the new antideoressant scored an average of 23.3. Since the graduate student knows the standard devlation of the scores on the dearession inventory for the population of people who are depressed, she intends to use a hypothesis test that uses the z-score of the sample mean es the test statistic (also knawn as the z test). First, she wants to make sure all the required assumptions are satisfied. Which of the following conditions is not a required assumption for the z test? O Each observation is independent of every other observation. O The sampling distribution of M foilows a normal distribution. O Members of the samiple are selected randomly. The mean of the scores on the deprassion inventory is the same for those who take the antidepressant and those who don't. O The standard deviation of the scores on the depression inventory, is the same for those who take the antidepressant and those who don't. Use the Distributions tool to firid the critical region for o 05. Use the Distributions tool to find the critical region for a = ,05. Standard Normel Distribution Mean- 0.0 Standard Deviation1.0 5000 1500 a500 0.674 8.574 The critical z-scores (the values for z-scores that separate the tails from the main body of the distribution, forming the critical regions) are 12.326 Calculate the z statistic, and use the Distributions tool to evaluate the null hypothesis, The z statistic is-245 The z statistic does not lie in the critical region for a two-tailed hypothesis test. Therefore, the nul hypothesis is not rejected does does not
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A graduate student is performing a study on a new antidepressant. The drug is supposed to reduce depression, but
the graduate student realizes that it may do nothing or even increase depression, so she decides to formulate
nondirectional hypotheses and conduct a two-tailed test. She knows that the average score for all depressed people
Is po = 25, with a standard deviation of a = 6. If she designates the mean for the population of depressed people
who take the antidepressant aN Partdeprussante she can identify the null and alternative hypotheses as:
Hot Panupressnt Po
Ha Hentidnprennant * 10
The sample of 36 depressad people who tried out the new antideoressant scored an average of 23.3.
Since the graduate student knows the standard devlation of the scores on the dearession inventory for the population
of people who are depressed, she intends to use a hypothesis test that uses the z-score of the sample mean es the
test statistic (also knawn as the z test). First, she wants to make sure all the required assumptions are satisfied.
Which of the following conditions is not a required assumption for the z test?
O Each observation is independent of every other observation.
O The sampling distribution of M foilows a normal distribution.
O Members of the samiple are selected randomly.
The mean of the scores on the deprassion inventory is the same for those who take the antidepressant and
those who don't.
O The standard deviation of the scores on the depression inventory, is the same for those who take the
antidepressant and those who don't.
Use the Distributions tool to firid the critical region for o 05.
Transcribed Image Text:Use the Distributions tool to find the critical region for a = ,05.
Standard Normel Distribution
Mean-
0.0
Standard Deviation1.0
5000
1500
a500
0.674
8.574
The critical z-scores (the values for z-scores that separate the tails from the main body of the distribution, forming
the critical regions) are
12.326
Calculate the z statistic, and use the Distributions tool to evaluate the null hypothesis, The z statistic is-245
The z statistic does not lie in the critical region for a two-tailed hypothesis test. Therefore, the nul hypothesis is
not rejected
does
does not
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