A gas mixture with the same number of moles of CO2 and H2 was prepared and heated to 700K where the initial total pressure was 12 Atm. The equilibrium constant for the reaction: CO2 (g) + H2 (g) ⇄ CO(g) + H2O(g)            is 23 at 700 K. What is the CO partial pressure after equilibrium is established?

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A gas mixture with the same number of moles of CO2 and H2 was prepared and heated to 700K where the initial total pressure was 12 Atm. The equilibrium constant for the reaction:

CO2 (g) + H2 (g) ⇄ CO(g) + H2O(g)            is 23 at 700 K.

What is the CO partial pressure after equilibrium is established?

Expert Solution
Step 1

Recall the given reaction and find expression of Kp

           CO2g + H2gCOg + H2Og       Kp=PCO×PH2OPCO2×PH2Kp for this reaction is 23 at 700 K

As initial total pressure is 12 atm and moles of each reactant is same.So it is evident that initial pressure of CO2 is 6 atm and initial pressure of H2 is 6 atm

Step 2

Construct ICE table

                               CO2g + H2(g) CO(g) + H2OgInitial pressure            6                6             0             0(atm)Pressure                  -x           -x               x            xChange(atm)Equilibrium              (6-x)       (6-x)        x            xPressure(atm)Find partial pressure of all reactants and productsPCO2= (6-x) , PH2  (6-x), PCO=x , PH2O=xSubstitute expression of Kp with this values            x26-x2=23           or,x6-x=4.796                      x=4.964 So partial pressure of CO is 4.964 atm

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