A gas is compressed from an initial volume of 0.42 m3 to a final volume of 0.12 m3. During the quasi-equilibrium process, the pressure changes with volume according to the relation P = aV 1 b, where a = 21200 kPa/m3 and b = 600 kPa. Calculate the work done during this process (a) by plotting the process on a P-V diagram and finding the area under the process curve and (b) by performing the necessary integrations.

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A: We'll use first law of thermodynamics here Q=∆U+W

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A: Solution :-  For polytropic process:-  P.V^n = constant .  Work done = (P2. V2 - P1 . V1) / (1-n)

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A:

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A: To derive the equation for the work done in an isothermal process.

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A:

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A:

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A:

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A: (a). the work done of the gas is

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A:

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A:

Q: It's a thermodynamics question.

A: a) The expression for the Work done W is given by,

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A:

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A:

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A:

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A: The PV diagram is shown above,