### Galvanic Cell Formation from Copper and TinA galvanic cell can be prepared from copper and tin. The following reactions represent the half-reactions for copper and tin:#### Copper Reaction:\[ \text{Cu}^{2+}(aq) + 2\text{e}^- \rightarrow \text{Cu}(s) \]\[ \text{E}^\circ = 0.34 \, \text{V} \]#### Tin Reaction:\[ \text{Sn}^{2+}(aq) + 2\text{e}^- \rightarrow \text{Sn}(aq) \]\[ \text{E}^\circ = -0.14 \, \text{V} \]### QuestionWhich of the following statements is true for the reactions above?1. The mass of the copper electrode will increase.2. Oxidation occurs at the copper electrode.3. \(\text{Sn}^{2+}\) will be reduced to \(\text{Sn}\) at the tin electrode.4. Tin will be produced at the tin electrode.### ExplanationIn a galvanic cell, the reduction occurs at the electrode with the higher reduction potential. Thus, copper ions will be reduced to copper metal, increasing the mass of the copper electrode. This makes the first statement true.

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A galvanic cell can be prepared from copper and tin. Which of the following statements is true? Cu2*(aq) + 2e¯ - → Cu(s) E° = 0.34 V Sn2*(aq) + 2e¯ - Sn(aq) E° = -0.14 V > The mass of copper electrode will increase. Oxidation occurs at the copper electrode O Sn2+ will be reduced to Sn at the tin electrode. O Tin will be produced at the tin electrode

A galvanic cell can be prepared from copper and tin. Which of the following statements is true? Cu2(aq) + 2e¯ - → Cu(s) E° = 0.34 V Sn2(aq) + 2e¯ - Sn(aq) E° = -0.14 V > The mass of copper electrode will increase. Oxidation occurs at the copper electrode O Sn2+ will be reduced to Sn at the tin electrode. O Tin will be produced at the tin electrode

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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