a function of the concentrations, at 18 °C. c (mmol/cm³) 84 165 390 800 s (mmol acet./g C) 1.50 2.15 3.50 5.10 a) Which is the most adequate isotherm: Langmuir, Temkin or Freundlich? Justify b) Calculate the magnitudes relevant for the chosen isotherm. Since the adsorption is given in a liquid solution, c and s are, respectively, equivalent to pressure (p) and adsorbed volume (v). Results: a) Freundlich isotherm is the most adequate: log s = -0.8751 + 0.5459 log c, R = 0.99978. (Langmuir R= 0.983; Temkin: R = 0.9745). b) k = 0.139 mmol Acet./g C and a = 0.5459.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The following table shows the acetone mols adsorbed on active carbon per gr of carbon, at a function of the concentrations, at 18 ºC.
a) Which is the most adequate isotherm: Langmuir, Temkin or Freundlich? Justify
b) Calculate the magnitudes relevant for the chosen isotherm.
Since the adsorption is given in a liquid solution, c and s are, respectively, equivalent to pressure (p) and adsorbed volume (v).

Results: a) Freundlich isotherm is the most adequate: log s = -0.8751 + 0.5459 log c, R = 0.99978. (Langmuir R = 0.983; Temkin: R = 0.9745).
b) k = 0.139 mmol Acet./g C and a = 0.5459.

 

a function of the concentrations, at 18 °C.
c ( mmol/cm³)
84
165
390
800
s (mmol acet./g C)
1.50
2.15
3.50
5.10
a) Which is the most adequate isotherm: Langmuir, Temkin or Freundlich? Justify
b) Calculate the magnitudes relevant for the chosen isotherm.
Since the adsorption is given in a liquid solution, c and s are, respectively, equivalent to
pressure (p) and adsorbed volume (v).
Results: a) Freundlich isotherm is the most adequate: log s = -0.8751 + 0.5459 log c, R =
0.99978. (Langmuir R = 0.983; Temkin: R = 0.9745).
b) k = 0.139 mmol Acet./g C and a = 0.5459.
Transcribed Image Text:a function of the concentrations, at 18 °C. c ( mmol/cm³) 84 165 390 800 s (mmol acet./g C) 1.50 2.15 3.50 5.10 a) Which is the most adequate isotherm: Langmuir, Temkin or Freundlich? Justify b) Calculate the magnitudes relevant for the chosen isotherm. Since the adsorption is given in a liquid solution, c and s are, respectively, equivalent to pressure (p) and adsorbed volume (v). Results: a) Freundlich isotherm is the most adequate: log s = -0.8751 + 0.5459 log c, R = 0.99978. (Langmuir R = 0.983; Temkin: R = 0.9745). b) k = 0.139 mmol Acet./g C and a = 0.5459.
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