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4) It is desired to absorb 90% of the acetone from a gas containing 1 mole% acetone in air in a continuous multi-stage absorption column using essentially pure water as the solvent. The total inlet gas flow is 30 mol s-1 and the inlet water flow is 90 mol s-1 . The equilibrium relation for the acetone is y = 2.53 x (as shown in the plot below). Find the number of equilibrium stages required. Note that since the solute is dilute, we may use the approximation that mole fractions are approximately equal to mole ratios.  answer is 6 stages    could steps be show on achieving this using the oeprating line given

4) It is desired to absorb 90% of the acetone from a gas containing 1 mole% acetone in air in a continuous multi-stage absorption column using essentially pure water as the solvent. The total inlet gas flow is 30 mol s-1 and the inlet water flow is 90 mol s-1 . The equilibrium relation for the acetone is y = 2.53 x (as shown in the plot below). Find the number of equilibrium stages required. Note that since the solute is dilute, we may use the approximation that mole fractions are approximately equal to mole ratios.  answer is 6 stages    could steps be show on achieving this using the oeprating line given

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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4) It is desired to absorb 90% of the acetone from a gas containing 1 mole% acetone in air in a continuous multi-stage absorption column using essentially pure water as the solvent. The total inlet gas flow is 30 mol s-1 and the inlet water flow is 90 mol s-1 . The equilibrium relation for the acetone is y = 2.53 x (as shown in the plot below). Find the number of equilibrium stages required. Note that since the solute is dilute, we may use the approximation that mole fractions are approximately equal to mole ratios. 

answer is 6 stages 

 

could steps be show on achieving this using the oeprating line given

The mole fraction of Gas at top of the column is Y₂ = 0.01 0.09 x 0.01 = 0.001 The operating line is represented as, X₁₂ = 1/7 ( X ₁₂ - X ₂) + X₂₁ The moles of pure air = 30 - 30 × 0.01 = 29.7 moles Therefore, Y₁ = 90 29.7 X + 0.001 Y₁ = 3X + 0.001 Plotting on the graph it sets off stages of approximately 6 stages
Transcribed Image Text:The mole fraction of Gas at top of the column is Y₂ = 0.01 0.09 x 0.01 = 0.001 The operating line is represented as, X₁₂ = 1/7 ( X ₁₂ - X ₂) + X₂₁ The moles of pure air = 30 - 30 × 0.01 = 29.7 moles Therefore, Y₁ = 90 29.7 X + 0.001 Y₁ = 3X + 0.001 Plotting on the graph it sets off stages of approximately 6 stages
acetone mole fraction in gas 0.014 0.013 0.012 0.011 0.01 0.009 0.008 0.007 0.006 0.005 0.004 0.003 0.002 0.001 0 0 0.001 0.002 0.003 acetone mole fraction in liquid 0.004 0.005
Transcribed Image Text:acetone mole fraction in gas 0.014 0.013 0.012 0.011 0.01 0.009 0.008 0.007 0.006 0.005 0.004 0.003 0.002 0.001 0 0 0.001 0.002 0.003 acetone mole fraction in liquid 0.004 0.005
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