A free electron is scattered across a photon with energy of 301 MeV. has a 50% loss in its energy, what should the scattering angle of the photon be?

icon
Related questions
Question

A free electron is scattered across a photon with energy of 301 MeV. has a 50% loss in its energy, what should the scattering angle of the photon be?

 

1:) 0 = 278°
2:) 0 = 2, 78°
3:) 0 = 5,66°
4:) 0 = 0°
5:) 0 = 3,34°
%3D
Transcribed Image Text:1:) 0 = 278° 2:) 0 = 2, 78° 3:) 0 = 5,66° 4:) 0 = 0° 5:) 0 = 3,34° %3D
Expert Solution
steps

Step by step

Solved in 5 steps with 5 images

Blurred answer