X-rays of wavelength 0.8 nm are Compton-scattered, the scattered beam is observed at an angle of 60.0° relative to the incident beam. Calculate the energy of the scattered X-ray photons.

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**Problem Statement:**

X-rays of wavelength 0.8 nm are Compton-scattered. The scattered beam is observed at an angle of 60.0° relative to the incident beam. Calculate the energy of the scattered X-ray photons.

**Explanation:**

This problem involves the Compton scattering of X-rays. In Compton scattering, an X-ray photon collides with an electron, resulting in a change in the photon's wavelength and direction. The change in wavelength is given by the Compton wavelength shift formula:

\[ \Delta \lambda = \frac{h}{m_ec} (1 - \cos \theta) \]

where:
- \( \Delta \lambda \) is the change in wavelength,
- \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)),
- \( m_e \) is the electron rest mass (\(9.109 \times 10^{-31} \, \text{kg}\)),
- \( c \) is the speed of light (\(3.00 \times 10^8 \, \text{m/s}\)),
- \( \theta \) is the angle of scattering.

The energy of the scattered photon can be calculated using the relation between energy and wavelength:

\[ E = \frac{hc}{\lambda} \]

**No graphs or diagrams are provided or needed for this problem.**
Transcribed Image Text:**Problem Statement:** X-rays of wavelength 0.8 nm are Compton-scattered. The scattered beam is observed at an angle of 60.0° relative to the incident beam. Calculate the energy of the scattered X-ray photons. **Explanation:** This problem involves the Compton scattering of X-rays. In Compton scattering, an X-ray photon collides with an electron, resulting in a change in the photon's wavelength and direction. The change in wavelength is given by the Compton wavelength shift formula: \[ \Delta \lambda = \frac{h}{m_ec} (1 - \cos \theta) \] where: - \( \Delta \lambda \) is the change in wavelength, - \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)), - \( m_e \) is the electron rest mass (\(9.109 \times 10^{-31} \, \text{kg}\)), - \( c \) is the speed of light (\(3.00 \times 10^8 \, \text{m/s}\)), - \( \theta \) is the angle of scattering. The energy of the scattered photon can be calculated using the relation between energy and wavelength: \[ E = \frac{hc}{\lambda} \] **No graphs or diagrams are provided or needed for this problem.**
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