A frameshift mutation occurs in a DNA strand. The mutation is a deletion of the two nucleotides indicated in the sequence below. 1. Rewrite the mutated DNA sequence. 2. Transcribe the given template strand of dna. 3. Translate the mRNA sequence.

Human Heredity: Principles and Issues (MindTap Course List)
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Author:Michael Cummings
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Chapter9: Gene Expression And Gene Regulation
Section: Chapter Questions
Problem 16QP: Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also,...
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A frameshift mutation occurs in a DNA strand. The mutation is a deletion of the two nucleotides indicated in the sequence below. 1. Rewrite the mutated DNA sequence. 2. Transcribe the given template strand of dna. 3. Translate the mRNA sequence.
TAC CTA CTC TAG TTA ACC ACA GTT GCC ATC
A frameshift mutation occurs in a DNA strand. The mutation is a deletion of the two
nucleotides indicated in the sequence above.
Re-write the mutated DNA sequence:
Transcribe the given template strand of DNA:
Second MRNA base
G.
UAU Tyr
UGU
Cys
UUU Phe uCU
UUC (F)
UCC Ser
()
UGC (C)
UAC
(s)
UAA Stop UGA Stop
UUA Leu UCA
UAG Ston GG Tm
Transcribed Image Text:TAC CTA CTC TAG TTA ACC ACA GTT GCC ATC A frameshift mutation occurs in a DNA strand. The mutation is a deletion of the two nucleotides indicated in the sequence above. Re-write the mutated DNA sequence: Transcribe the given template strand of DNA: Second MRNA base G. UAU Tyr UGU Cys UUU Phe uCU UUC (F) UCC Ser () UGC (C) UAC (s) UAA Stop UGA Stop UUA Leu UCA UAG Ston GG Tm
Second MRNA base
C.
Phe
UUC (F ucc Ser UAC (Y UGC (C)
UUU
UCU
UAU
Tyr
UGU
(S)
UAA Stop UGA Stop
UAG Stop UGG Trp (W) G
UUA
Leu
UCA
UUG (L) UCG
CUU
CU
CAU THis CGU
CUC Leu CCC Pro CAC (H) CGC Arg
CUA (L) cCA P) CAA Gin CGA (R)
CAG (Q) CGG
CUG
CCG
AUU
ACU
AAU
Asn
AGU
Ser
lle
(1)
ACA
AUC
ACC Thr AAC (N) AGC (S)
AUA
(T)
AAA
AGA
Lys
(K)
Arg
(R)
AUG Met (M ACG
start
AAG
AGG
GUU
GAU Asp GGU
GUC Val GCC Ala GAC (D) GGC Gly
(G)
GCU
C.
GUA
(V)
GCA
(A)
GAA Glu GGA
GUG
GCG
GAG
(E)
GGG
Translate the MRNA sequence:
Use the 3-letter code for amino acids. If a stop codon is encountered use the word
"stop", without "
23
First mRNA base (5' end of codon)
Third mRNA base (3' end of codon)
Transcribed Image Text:Second MRNA base C. Phe UUC (F ucc Ser UAC (Y UGC (C) UUU UCU UAU Tyr UGU (S) UAA Stop UGA Stop UAG Stop UGG Trp (W) G UUA Leu UCA UUG (L) UCG CUU CU CAU THis CGU CUC Leu CCC Pro CAC (H) CGC Arg CUA (L) cCA P) CAA Gin CGA (R) CAG (Q) CGG CUG CCG AUU ACU AAU Asn AGU Ser lle (1) ACA AUC ACC Thr AAC (N) AGC (S) AUA (T) AAA AGA Lys (K) Arg (R) AUG Met (M ACG start AAG AGG GUU GAU Asp GGU GUC Val GCC Ala GAC (D) GGC Gly (G) GCU C. GUA (V) GCA (A) GAA Glu GGA GUG GCG GAG (E) GGG Translate the MRNA sequence: Use the 3-letter code for amino acids. If a stop codon is encountered use the word "stop", without " 23 First mRNA base (5' end of codon) Third mRNA base (3' end of codon)
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