A force of magnitude F acting in the x-direction on a 2.0-kg object varies in time as shown in the figure.

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A force of magnitude \( F \) acting in the \( x \)-direction on a 2.0-kg object varies in time as shown in the figure.

**Graph Explanation:**
- The graph plots force \( F(t) \) in newtons (N) on the y-axis against time \( t \) in seconds (s) on the x-axis.
- From \( t = 0 \) to \( t = 1 \) second, the force increases linearly from 0 N to 4 N.
- From \( t = 1 \) second to \( t = 3 \) seconds, the force remains constant at 4 N.
- From \( t = 3 \) seconds to \( t = 4 \) seconds, the force decreases linearly back to 0 N.
- From \( t = 4 \) seconds to \( t = 5 \) seconds, the force remains at 0 N.

**Problem Statement:**
Find the final velocity of the object if it is initially moving along the \( x \)-axis with a velocity of 2.0 m/s.

**Answer Choices:**
- a. 8.0 m/s
- b. 12 m/s
- c. 6.0 m/s
- d. 20 m/s
- e. 4.0 m/s
- f. None of these choices.
- g. 2.0 m/s
- h. 24 m/s
Transcribed Image Text:A force of magnitude \( F \) acting in the \( x \)-direction on a 2.0-kg object varies in time as shown in the figure. **Graph Explanation:** - The graph plots force \( F(t) \) in newtons (N) on the y-axis against time \( t \) in seconds (s) on the x-axis. - From \( t = 0 \) to \( t = 1 \) second, the force increases linearly from 0 N to 4 N. - From \( t = 1 \) second to \( t = 3 \) seconds, the force remains constant at 4 N. - From \( t = 3 \) seconds to \( t = 4 \) seconds, the force decreases linearly back to 0 N. - From \( t = 4 \) seconds to \( t = 5 \) seconds, the force remains at 0 N. **Problem Statement:** Find the final velocity of the object if it is initially moving along the \( x \)-axis with a velocity of 2.0 m/s. **Answer Choices:** - a. 8.0 m/s - b. 12 m/s - c. 6.0 m/s - d. 20 m/s - e. 4.0 m/s - f. None of these choices. - g. 2.0 m/s - h. 24 m/s
Expert Solution
Step 1

Given :

  • Mass(m)=2kg
  • initial velocity=2m/s

To find:

Final velocity

steps

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