A cart that can move along a straight track has a mass of 3.00 kg and an initial velocity of 4.00 m/s in the negative x-direction. The cart is then subjected to a net force that is initially in the positive x-direction, but which then eventually switches direction to the negative x-direction, as shown in the graph of force as a function of time below. The force is directed only in the +x or -x direction. F; (N) +30- +20- +10+ 0- ++1 (s) 30 25 10 20 -10+ -20+ (a) Complete the table below to show the cart's momentum and velocity at the indicated times. Use + and - signs, as appropriate. Time Momentum Velocity t= 0s kg • m/s v = m/s t = 20 s p = kg • m/s V = m/s t = 25 s p = kg · m/s m/s V =

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A cart that can move along a straight track has a mass of 3.00 kg and an initial velocity of 4.00 m/s in the negative x-direction. The cart is then subjected to a net force that is initially in the positive
x-direction, but which then eventually switches direction to the negative x-direction, as shown in the graph of force as a function of time below. The force is directed only in the +x or -x direction.
F (N)
+30-
+20-
+10-
0-
Þ1(s)
10
20
25
30
-10-
-20+
(a) Complete the table below to show the cart's momentum and velocity at the indicated times. Use + and - signs, as appropriate.
Time
Momentum
Velocity
t = 0s
p =
kg • m/s
V =
m/s
t = 20 s
p =
kg • m/s
V =
m/s
t = 25 s
p =
kg • m/s
V =
m/s
(b) The cart's momentum at t = 20 s is exactly the same as its momentum at t =
s.
Transcribed Image Text:A cart that can move along a straight track has a mass of 3.00 kg and an initial velocity of 4.00 m/s in the negative x-direction. The cart is then subjected to a net force that is initially in the positive x-direction, but which then eventually switches direction to the negative x-direction, as shown in the graph of force as a function of time below. The force is directed only in the +x or -x direction. F (N) +30- +20- +10- 0- Þ1(s) 10 20 25 30 -10- -20+ (a) Complete the table below to show the cart's momentum and velocity at the indicated times. Use + and - signs, as appropriate. Time Momentum Velocity t = 0s p = kg • m/s V = m/s t = 20 s p = kg • m/s V = m/s t = 25 s p = kg • m/s V = m/s (b) The cart's momentum at t = 20 s is exactly the same as its momentum at t = s.
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