A cart that can move along a straight track has a mass of 3.00 kg and an initial velocity of 4.00 m/s in the negative x-direction. The cart is then subjected to a net force that is initially in the positive x-direction, but which then eventually switches direction to the negative x-direction, as shown in the graph of force as a function of time below. The force is directed only in the +x or -x direction. F; (N) +30- +20- +10+ 0- ++1 (s) 30 25 10 20 -10+ -20+ (a) Complete the table below to show the cart's momentum and velocity at the indicated times. Use + and - signs, as appropriate. Time Momentum Velocity t= 0s kg • m/s v = m/s t = 20 s p = kg • m/s V = m/s t = 25 s p = kg · m/s m/s V =

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**Educational Content on Force and Momentum**

### Description

A cart that can move along a straight track has a mass of **3.00 kg** and an initial velocity of **4.00 m/s** in the negative x-direction. The cart is then subjected to a net force that is initially in the positive x-direction, but which eventually switches direction to the negative x-direction, as shown in the graph of force as a function of time below. The force is directed only in the +x or -x direction.

### Graph Explanation

The graph displays the net force \( F_x \) over time \( t \).

- **Vertical Axis (Force \( F_x \) in Newtons):** Ranges from -20 N to +30 N.
- **Horizontal Axis (Time \( t \) in seconds):** Ranges from 0 to 35 seconds.
  
Key features include:
- From 0 s to 5 s, the force is +20 N.
- From 5 s to 15 s, the force decreases linearly to -10 N at 15 s.
- From 15 s to 25 s, the force is constant at 0 N.
- From 25 s to 30 s, the force increases to +20 N.
- From 30 s to 35 s, the force is constant at +20 N.

### Tasks

(a) **Complete the table below to show the cart's momentum and velocity at the indicated times. Use + and − signs, as appropriate.**

| Time       | Momentum               | Velocity          |
|------------|------------------------|-------------------|
| \( t = 0 \, \text{s} \) | \( p = \) ___________________ kg·m/s | \( v = \) ___________________ m/s |
| \( t = 20 \, \text{s} \) | \( p = \) ___________________ kg·m/s | \( v = \) ___________________ m/s |
| \( t = 25 \, \text{s} \) | \( p = \) ___________________ kg·m/s | \( v = \) ___________________ m/s |

(b) **The cart's momentum at \( t = 20 \, \text{s} \) is exactly the same as its momentum at \( t = \) ______ s.** 

Students are tasked with calculating the momentum and velocity of the cart at specified times based on force interactions
Transcribed Image Text:**Educational Content on Force and Momentum** ### Description A cart that can move along a straight track has a mass of **3.00 kg** and an initial velocity of **4.00 m/s** in the negative x-direction. The cart is then subjected to a net force that is initially in the positive x-direction, but which eventually switches direction to the negative x-direction, as shown in the graph of force as a function of time below. The force is directed only in the +x or -x direction. ### Graph Explanation The graph displays the net force \( F_x \) over time \( t \). - **Vertical Axis (Force \( F_x \) in Newtons):** Ranges from -20 N to +30 N. - **Horizontal Axis (Time \( t \) in seconds):** Ranges from 0 to 35 seconds. Key features include: - From 0 s to 5 s, the force is +20 N. - From 5 s to 15 s, the force decreases linearly to -10 N at 15 s. - From 15 s to 25 s, the force is constant at 0 N. - From 25 s to 30 s, the force increases to +20 N. - From 30 s to 35 s, the force is constant at +20 N. ### Tasks (a) **Complete the table below to show the cart's momentum and velocity at the indicated times. Use + and − signs, as appropriate.** | Time | Momentum | Velocity | |------------|------------------------|-------------------| | \( t = 0 \, \text{s} \) | \( p = \) ___________________ kg·m/s | \( v = \) ___________________ m/s | | \( t = 20 \, \text{s} \) | \( p = \) ___________________ kg·m/s | \( v = \) ___________________ m/s | | \( t = 25 \, \text{s} \) | \( p = \) ___________________ kg·m/s | \( v = \) ___________________ m/s | (b) **The cart's momentum at \( t = 20 \, \text{s} \) is exactly the same as its momentum at \( t = \) ______ s.** Students are tasked with calculating the momentum and velocity of the cart at specified times based on force interactions
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