Three forces acting on an object are given by F₁ = (−2.2î + 6.85ĵ) N, F₂ = (4.75î – 1.25ĵ) N, and F3 = (-401) N. The object experiences an acceleration of magnitude 3.80 m/s².(a) What is the direction of the acceleration?98.50XNote that the direction of the acceleration is the same as the direction of the net force.° (counterclockwise from the +x-axis)(b) What is the mass of the object?9.964kg(c) If the object is initially at rest, what is its speed after 11.0 s?41.8m/s(d) What are the velocity components of the object after 11.0 s? (Let the velocity be denoted by v.)✓ = -41.34m/s+6.18

The answer is given below Explanation:Step 1:(a) 171.5° counter clockwise from +x-axisStep 2:Step 3:…

Answered: Three forces acting on an object are…

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