**Educational Transcript and Explanation****Problem Description:**A 3.0 kg toy car can move along an x-axis. The figure provides the force \( F_x \) acting on the car, which begins at rest at time \( t = 0 \). The scale on the \( F_x \) axis is set by \( F_{xs} = 7.0 \, \text{N} \). In unit-vector notation, find:(a) \( \vec{P} \) at \( t = 2.0 \, \text{s} \) (b) \( \vec{P} \) at \( t = 9.0 \, \text{s} \) (c) \( \vec{V} \) at \( t = 7.0 \, \text{s} \) ---**Graph Explanation:**The graph displays the force \( F_x \) (in newtons) exerted on the toy car over time \( t \) (in seconds). The y-axis represents force, while the x-axis represents time. The key points on the graph are:- Force increases linearly from \( 0 \, \text{s} \) to \( 2 \, \text{s} \).- Force remains constant between \( 2 \, \text{s} \) and \( 4 \, \text{s} \).- Force decreases to zero at \( 6 \, \text{s} \).- Force becomes negative until \( 8 \, \text{s} \) and returns to zero after \( 8 \, \text{s} \).The value of \( F_x \) at its peak is indicated by \( F_{xs} \).---**Problem Solutions:**(a) At \( t = 2.0 \, \text{s} \): - The momentum \( \vec{P} \) is given as: - Number: 14 - \( \hat{i} \): 0 - \( \hat{j} \): 0 - \( \hat{k} \): 0- Units: kg·m/s or N·s(b) At \( t = 9.0 \, \text{s} \): - The momentum \( \vec{P} \) is given as: - Number: 63 - \( \

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A 3.0 kg toy car can move along an x axis. The figure gives Fx of the force acting on the car, which begins at rest at time t = 0. The scale on the Fx axis is set by Fxs = 7.0 N. In unit-vector notation, what is P at (a)t = 2.0s and (b)t = 9.0 s,(c) what is att = 7.0 s? (a) Number 14 (b) Number i 63 (c) Number i <•+ + 0 0 0 Fx (N) F -F 2 4 + + 6 0 0 0 t(s) k Units k Units k Units kg.m/s or N-s kg.m/s or N-s

A 3.0 kg toy car can move along an x axis. The figure gives Fx of the force acting on the car, which begins at rest at time t = 0. The scale on the Fx axis is set by Fxs = 7.0 N. In unit-vector notation, what is P at (a)t = 2.0s and (b)t = 9.0 s,(c) what is att = 7.0 s? (a) Number 14 (b) Number i 63 (c) Number i <•+ + 0 0 0 Fx (N) F -F 2 4 + + 6 0 0 0 t(s) k Units k Units k Units kg.m/s or N-s kg.m/s or N-s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Educational Transcript and Explanation**

**Problem Description:**
A 3.0 kg toy car can move along an x-axis. The figure provides the force \( F_x \) acting on the car, which begins at rest at time \( t = 0 \). The scale on the \( F_x \) axis is set by \( F_{xs} = 7.0 \, \text{N} \). In unit-vector notation, find:

(a) \( \vec{P} \) at \( t = 2.0 \, \text{s} \)
(b) \( \vec{P} \) at \( t = 9.0 \, \text{s} \)
(c) \( \vec{V} \) at \( t = 7.0 \, \text{s} \)

---

**Graph Explanation:**
The graph displays the force \( F_x \) (in newtons) exerted on the toy car over time \( t \) (in seconds). The y-axis represents force, while the x-axis represents time. The key points on the graph are:

- Force increases linearly from \( 0 \, \text{s} \) to \( 2 \, \text{s} \).
- Force remains constant between \( 2 \, \text{s} \) and \( 4 \, \text{s} \).
- Force decreases to zero at \( 6 \, \text{s} \).
- Force becomes negative until \( 8 \, \text{s} \) and returns to zero after \( 8 \, \text{s} \).

The value of \( F_x \) at its peak is indicated by \( F_{xs} \).

---

**Problem Solutions:**

(a) At \( t = 2.0 \, \text{s} \):
- The momentum \( \vec{P} \) is given as:
- Number: 14
- \( \hat{i} \): 0
- \( \hat{j} \): 0
- \( \hat{k} \): 0
- Units: kg·m/s or N·s

(b) At \( t = 9.0 \, \text{s} \):
- The momentum \( \vec{P} \) is given as:
- Number: 63
- \( \

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