A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 10 m/s. Give the initial conditions. x(0) = x'(0) = x(t) = m Find the equation of motion. m m/s
A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 10 m/s. Give the initial conditions. x(0) = x'(0) = x(t) = m Find the equation of motion. m m/s
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![7.
DETAILS
x(0) =
***********
A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 10 m/s.
Give the initial conditions.
x'(0) =
ZILLDIFFEQMODAP11 5.1.006.EP.
x(t) =
m
Find the equation of motion.
m
m/s
MY NOTES](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff275352f-9efa-45bf-91ed-ab737bf8cf55%2F5dbcb71a-ce7c-4ca1-920f-ee7dc4e88e67%2Fbw9flw9_processed.png&w=3840&q=75)
Transcribed Image Text:7.
DETAILS
x(0) =
***********
A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 10 m/s.
Give the initial conditions.
x'(0) =
ZILLDIFFEQMODAP11 5.1.006.EP.
x(t) =
m
Find the equation of motion.
m
m/s
MY NOTES
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