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a For the following unbalanced chemical equation, suppose that exactly 5.85 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. S(s) + H2SO4(aq) → SO2(g) + H20(1) Limiting reactant: Mass of SO2 = Mass of H2O = b For the following unbalanced chemical equation, suppose that exactly 6.50 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. MnO2(s) + H2S04(aq) → Mn(SO4)2(8) + H2O(1) Limiting reactant: Mass of Mn(SO4)2 g Mass of H20 = g

a For the following unbalanced chemical equation, suppose that exactly 5.85 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. S(s) + H2SO4(aq) → SO2(g) + H20(1) Limiting reactant: Mass of SO2 = Mass of H2O = b For the following unbalanced chemical equation, suppose that exactly 6.50 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. MnO2(s) + H2S04(aq) → Mn(SO4)2(8) + H2O(1) Limiting reactant: Mass of Mn(SO4)2 g Mass of H20 = g

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This question has multiple parts. Work all the parts to get the most points. a For the following unbalanced chemical equation, suppose that exactly 5.85 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. S(s) + H2 SO4(a) → SO2 (9) + H20(1) Limiting reactant: Mass of SO2 Mass of H20 = b For the following unbalanced chemical equation, suppose that exactly 6.50 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. MnO2 (s) + H2S04 (aq) → Mn(SO4)2(s) + H20(1) Limiting reactant: Mass of Mn(SO4)2 Mass of H20 =
Transcribed Image Text:This question has multiple parts. Work all the parts to get the most points. a For the following unbalanced chemical equation, suppose that exactly 5.85 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. S(s) + H2 SO4(a) → SO2 (9) + H20(1) Limiting reactant: Mass of SO2 Mass of H20 = b For the following unbalanced chemical equation, suppose that exactly 6.50 g of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). Enter the formula for the limiting reactant. MnO2 (s) + H2S04 (aq) → Mn(SO4)2(s) + H20(1) Limiting reactant: Mass of Mn(SO4)2 Mass of H20 =
Expert Solution
Step 1: Reaction (a) Balanced chemical equation

The given chemical reaction is :

  Ss + H2SO4aq → SO2g + H2Ol

Balancing the given chemical reaction :

  • Balancing Oxygen atoms:

There are 4 Oxygen atoms on reactants side and 3 Oxygen atoms on products side. So Multiplying H2O with 2 gives:

 Ss + H2SO4aq → SO2g + 2H2Ol

  • Balancing Hydrogen atoms:

There are 2 Hydrogen atoms on reactants side and 4 Hydrogen atoms on products side. So Multiplying H2SO4 with 2 gives:

 Ss + 2H2SO4aq → SO2g + 2H2Ol

  • Balancing Sulfur atoms:

There are 3 Sulfur atoms on reactants side and 1 Sulfur atom on products side. So Multiplying SO2 with 3 gives:

 S(s) + 2H2SO4(aq) → 3SO2(g) + 2H2O(l)

Number of atoms on reactants side is equal to the number of corresponding atoms on the products side

Therefore balanced form of chemical equation is:

 S(s) + 2H2SO4(aq) → 3SO2(g) + 2H2O(l)

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