A food refrigerator is to provide a 15,000-kJ/h cooling effect while rejecting 22100 kJ/h of heat. Calculate the COP of this refrigerator. (Round the final answer to one decimal place.) Reservoir Он R 15,000 kJ/h Reservoir The COP of the refrigerator is
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- A heat pump is used to extract heat from the outside atmosphere to heat the inside of a building. On a day when the outside air temperature is Tc°C, the heat pump is operating to a COP of 3.7, maintaining the inside temperature of the building at Th°C. If the building is losing heat at the rate of 53,709 kJ/hour in these conditions, determine how much power (kW) must be supplied to a heat pump? Keep two decimal placesThe thermal effiency of a general heat engine is 35 percent, and it produces 60 hp. At what rate is heat transferred to this engine, in kJ/s?In a given process, a heat engine requires 2500J of energy and exhausts 1200J of heat. What is its efficiency?
- A heat engine must provide 1000 Watts of power. Assuming it has an efficiency of 0.32, how much heat must be supplied to the engine, in Watts?Answers are included, but I need the work.An engine uses about 0.24 kg of fuel/kW-hr. If the heating value of the fuel is 50 MJ/kg, what is the thermal efficiency?
- Q1. Solve all parts Depicted in Fig. Q1 is an irreversible refrigerator whose compressor is powered by a reversible heat engine that operates between temperature extremes Thot = 473K and cold = 293 K. The refrigerator depicted uses a dichlorodifluoromethane refrigerant (Refrigerant 12) circulating by means of the compressor at mass flow rate = 0.15 kg/s. The other components of the refrigerator are two heat exchangers in the form of an evaporator and a condenser, and a throttle valve. Information recorded at the state points depicted in Fig. Q1 is as follows: State point 1: dryness fraction x₁ = 1 and temperature t₁ = 15 °C. State point 2: dryness fraction x2 = 0 and temperature t₂ = 15°C. State point 3: wet vapour at temperature t₁ = -20°C. State point 4: wet vapour at temperature t₁ = -20°C. (a) Determine the thermal efficiency NR of the reversible heat engine depicted in Fig. Q1, and consequently determine power -W4-1 supplied to the compressor given that the rate of heat supplied…A perfectly insulated cubical office with length 10 m3 has an air conditioner that cools the house to 17 °C from 38 °C within 15 min with COPref of 3. If the density of air is taken as 1.225 kg/m3 with cy=0.72 kJ/kg °C and cp = 1.0 kJ/kg °C, determine the rate of heat removal (in kW) from the house, power used by the air conditioner and the cost of electricity (in Rands) for 3 hours in a building with six similar offices at a tariff of 280 c/kWh.I have been working on this problem for a while and keep getting wrong answers with many different meathods how do I solve for Q0 here?
- You are considering two heaters in your house which must provide 10kW of heating. You expect to run it for 100 days per year, 16 hours per day. The first heater is gas and has an effiency of 40% but gas costs .01 cents per kWhr (kilowatt - hour) The electric heater is 82% efficient but the cost of electricity is .03 cents per kWhr Which is the cheaper option?A central power plant, rated at 500,000 kW, generates steam at 500 K and discards heat to a river at 300 K. If the thermal efficiency of the plant is 80% of the maximum possible value, how much heat is discarded to the river at rated power?3.3 Would it be possible to use a normal domestic refrigerator as a heat source for a small hot tub or whirlpool? If so, what would you estimate to be the maximum heating rate and temperature that a 300 gal whirlpool could reach using a refrigerator that is sized to use a 1 hp electric compressor designed with an evaporator temperature of 10 ° F and condensing temperature of 125 ° F?