(a) Fir the useful power output of an elevator motor that Lifts a 2500-kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2500 kg is raised in height, but the full 10,000 kg is accelerated.
(a) Fir the useful power output of an elevator motor that Lifts a 2500-kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2500 kg is raised in height, but the full 10,000 kg is accelerated.
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Transcribed Image Text:(a) Fir the useful power output of an elevator motor that Lifts a 2500-kg load a
height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s.
Note that the total mass of the counterbalanced system is 10,000 kg-so that
only 2500 kg is raised in height, but the full 10,000 kg is accelerated.
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