(a) Find the useful power output (in W) of an elevator motor that lifts a 2200 kg load a height of 45.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2200 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) W (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? (Enter a number.) cents

(a) Find the useful power output (in W) of an elevator motor that lifts a 2200 kg load a height of 45.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2200 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) W (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? (Enter a number.) cents

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(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) 250.000 X W (b) What does it cost (in cents), if electricity is $0.0900 per kWh? (Enter a number.) 0.625 X cents +
(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) X W 72100 (b) What does it cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) 2.163 X cents
Consider an elevator car (lift) with a mass of 700kg which call carry up to 600kg of passengers. Use g = 10 ms. An electric motor is used to raise the elevator with a full load from the ground floor to the third floor, 9 m higher, in 30 s. Calculate the total energy needed and the power of motor required. 12 MJ and 2kW 12400 J and 2400 W 11700 J and 3900 W 48 kJ and 2400 W
can someone answer these for me please? Thank you!
Using energy considerations, calculate the average force (in N) a 69.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 6.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him. (Enter a number.)
An elevator motor lifts a 2750-kg load to a height of 37m in 12.5s. Find the useful power output of the elevator motor, if it also increases the speed from rest to 3.95 m/s. Assume that the total mass of the counterbalanced system is 10,000 kg — so that only 2750 kg is raised in height, but the full 10,000 kg is accelerated. How much does it cost, in dollars per hour, if the electricity cost is $0.075 per kW⋅h?
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an aircraft carrier was sent out to the south china sea to heigten the tensions between the disputed countries. lets say this aircraft carrier has a top speed of 39 km/hr (i know very slow) and da engine has a power 63,400 kW. a) find out the force friction that is on the aircraft carrier when its going to a top speed of it. b) find out how fast this ship is gonna go when its travelling against a wind force of 2,100,000 N. please help thank u please! :)