(a) Find the useful power output (in W) of an elevator motor that lifts a 2200 kg load a height of 45.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2200 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) W (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? (Enter a number.) cents
(a) Find the useful power output (in W) of an elevator motor that lifts a 2200 kg load a height of 45.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2200 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) W (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? (Enter a number.) cents
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(a) Find the useful power output (in W) of an elevator motor that lifts a 2200 kg load a height of 45.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2200 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) W (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? (Enter a number.) cents
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