a) Find the useful power output (in W) of an elevator motor that lifts a 2300 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2300 kg is raised in height, but the full 10,000 kg is accelerated. ? W (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? ? cents
a) Find the useful power output (in W) of an elevator motor that lifts a 2300 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2300 kg is raised in height, but the full 10,000 kg is accelerated. ? W (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? ? cents
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter7: Work, Energy, And Energy Resources
Section: Chapter Questions
Problem 39PE: (a) Find the useful power output of an elevator motor that lifts a 2500-kg load a height of 35.0 m...
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a) Find the useful power output (in W) of an elevator motor that lifts a 2300 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2300 kg is raised in height, but the full 10,000 kg is accelerated.
? W
(b) What does it cost (in cents), if electricity is $0.0900 per kW · h?
? cents
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